Answer:
Ball hits the ground after 4.5 sec
Step-by-step explanation:
Let a -1, so that the leading coefficient is positive
So our quadratic is

The key coefficients of two binomial variables can be 1 and 16, or 2 and 8, or 4 and 4, for the leading coefficient of 16.
Yet they can't actually be 4 and 4 because the linear (x) term coefficient has to be a multiple of 4, which it isn't and leading coefficients 1 and 16 on the binomial factors is not likely.
So, 2 and 8 taken as the leading coefficients of two binomial factors.
For constant 405, possible factorizations are 

Taking first factor, thus we find negative value for given time t. But second time equivalent to zero gives the value of 4.5 for t
Thus ball hits the ground after 4.5 sec
.
Mr. Ramirez can use many different group sizes, but the largest group size possible is 8. This results in 16/8=2 sixth-grade groups and 24/8=3 seventh-grade groups.
We can cosider this to be a difference of 2 squares so
4x^4 - 9x^2 = (2x^2 - 3x)(2x^2 + 3x) so D is one answer
also we could take x^2 out and get
x^2(4x^2 - 9) = C