If you begin with the basic equation of a vertical parabola: y-k=a(x-h)^2, where (h,k) is the vertex, then that equation, when the vertex is (-3,-2), is
y + 2 = a (x + 3)^2. If we solve this for y, we get
y = a(x+3)^2 - 2. Thus, eliminate answers A and D. That leaves B, since B correctly shows (x+3)^2.
Answer:
01–78
Step-by-step explanation:
Edge 2020/2021
<span>Answer:
The cylinder has equation y^2 + z^2 = 1 (with x in [0, 2]).
So, we can write the volume â«â«â« 1 dV as
â«(x = 0 to 2) â«(z = -1 to 1) â«(y = -âš(1 - z^2) to âš(1 - z^2)) 1 dy dz dx.</span>
