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katen-ka-za [31]
3 years ago
15

2. If a gambler makes repeated wagers, each with a probability of winning equal to 0.40, what is

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
4 0

the formula for the probability that they lose their first 5 wagers is  0.60^5 and probability is  0.078 .

<u>Step-by-step explanation:</u>

Here we have , If a gambler makes repeated wagers, each with a probability of winning equal to 0.40 , We need to find what is  the formula for the probability that they lose their first 5 wagers . Let's find out:

According to question , Probability of winning is 0.40 , so for losing :

⇒ 1-0.40

⇒ 0.60

Now , Probability that they lose their first 5 wagers is given by :

⇒ 0.60(0.60)(0.60)(0.60)(0.60)

⇒ 0.60^5

⇒ 0.078

Therefore , the formula for the probability that they lose their first 5 wagers is  0.60^5 and probability is  0.078 .

Umnica [9.8K]3 years ago
3 0

The probability of losing first 5 wagers is (0.6)⁵

<u>Explanation:</u>

The probability of winning = 0.4

The probability of losing = 1 - 0.4

                                      = 0.6

Probability of losing their first 5 wagers = ?

Probability of losing first 5 wagers = (0.6)⁵

Therefore, the probability of losing first 5 wagers is (0.6)⁵

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Courtney is twice as old as Andre and three years older than Natalie. Courtney is half Shari's age. The difference between Shari
lesantik [10]

The question does not seem complete, but I'll represent the statement mathematically and look for their ages each. This is because the worst they can ask for is their ages.

Let C stand for Courtney's age, A for Andrei's age, N for Natalie's age and S for Shari's age. From the question we can deduce the following:

C = 2A

C = N + 3

C = S/2

S - N = C + A

S = 2C, N = C - 3 and A = C/2, therefore we have

2C - (C - 3) = C + C/2

C + 3 = C + C/2

C/2 = 3 and C = 6

A = C/2

A= 6/2

A = 3

N = C - 3

N = 6 - 3

N = 3

S = 2C

S = 2 x 6

S = 12.

C = 6, A = 3, N = 3 and S = 12

8 0
3 years ago
Please answer this correctly
liraira [26]
Answer:
2156/9

Explanation:
The question states all the necessary values that we need for the ratio. The company created 2156 board games and 9 card games.

However, what we need to pay attention to here is the order of the ratio.

Because the question is “What is the ratio of the number of board games to the number of card games”, we know that we need to write the ratio so the number of board games is first.

Additionally, ratios can also be written like fractions. The first number of the ratio would be the top number/numerator in fraction form.

Therefore, the ratio of the number of board games to the number of card games is 2156:9

I hope this helps!
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3 years ago
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Which container holds more, a Elgin millimeter carton, or a 1 L bottle
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The answer would be a 1 Liter bottle, because a liter is 33 oz rounded and and Elgin millimeter container is 25 oz.
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Step-by-step explanation:

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Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
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