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Vladimir [108]
3 years ago
14

What is the product? (negative 3 s + 2 t)(4 s minus t)

Mathematics
2 answers:
lapo4ka [179]3 years ago
8 0

Answer:

-12s^2 + 11st - 2t^2.

Step-by-step explanation:

(-3s + 2t)(4s - t)

= -3s(4s - t) + 2t(4s - t)

= -12s^2 + 3st + 8st - 2t^2

= -12s^2 + 11st - 2t^2.

natima [27]3 years ago
7 0

Answer:

3

Step-by-step explanation:

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djverab [1.8K]

I'll assume the ODE is

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Solve the homogeneous ODE,

y'' - 3y' + 2y = 0

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y = C_1 e^x + C_2 e^{2x}

For nonhomogeneous ODE (1),

y'' - 3y' + 2y = e^x

consider the ansatz particular solution

y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x

Substituting this into (1) gives

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For the nonhomogeneous ODE (2),

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take the ansatz

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y'' - 3y' + 2y = e^{-x}

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Then the general solution to the ODE is

\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}

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