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makkiz [27]
3 years ago
6

Graph the linear equation. 3x−4y=12 Please show it on a graph

Mathematics
1 answer:
baherus [9]3 years ago
5 0

Answer: The graph is attached.

Step-by-step explanation:

By definition, the line intersects the y-axis when x=0.

Then, in order to find the y-intercept, substitute x=0 into the equation and solve for "y":

3(0)-4y=12\\\\y=\frac{12}{-4}\\\\y=-3

By definition, the line intersects the x-axis when y=0.

Then, in order to find the x-intercept, you can substitute y=0 into the equation and then you must solve for "x". Then you get:

3x-4(0)=12\\\\x=\frac{12}{3}\\\\x=4

Knowing that the line passes through the points (0,-3) and (4,0), you can graph it (The graph is attached).

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4 = -8Z - 7 + 8z<br> Giving the brainliest to whoever gets the right answer.
liubo4ka [24]

Answer:

No Solution

Step-by-step explanation:

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Three consecutive vertices of a parallelogram are (– 2, 1); (1, 0) and (4, 3). Find the coordinate of the fourth vertex and find
antiseptic1488 [7]

Answer:

D(1,4) - the fourth vertex, the area is equal to 12

Step-by-step explanation:

A(2,-1), B(1,0),C(4,3), They are consecutive, we need to find the point D, find the midpoint of AC (O)

xo= (xA+xc)/2    x0= (-2+4)/2=1

y0=(yA+yC)/2    y0= (1+3)/2=2

0(1,2)

O is the midpoint of BD, so let's find the vertex D

X0= (xB+xD)/2     1= (1+xD)/2   xD=1

y0= (yB+yD)/2      2= (0+yD)/2    yD=4

D(1,4)

the vector DA is (-2-1, 1-4)= (-3,-3)

the vector DC is (4-1, 3-4)= (3,-1)

The modul of DC is sqrt ((-3)^2+(-3)^2)= 3*sqrt2(the length of the side Dc)

The modul of DA is sqrt (3^2+(-1)^2)= sqrt10(the length of the side DA)

cosD= (-3*3+(-3)(-1))/3*sqrt2*sqrt10=-6/3*2*sqrt5=-1/sqrt5

sinD= sqrt (1- 1/5)=2/ sqrt5

S=3sqrt2*sqrt10*2/sqrt5= 12

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3 years ago
I need help with this math problem please
Yanka [14]

Answer:

x=12

Step-by-step explanation:

90 = x + 42 + 3x

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7 0
3 years ago
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3(x^2+1/x^2)-16(x+1/x)+26=0<br>​
Anuta_ua [19.1K]

Answer:

MULTIPLY!!!!!11!!!!!!!

Step-by-step explanation:

3x2+1/x2-26

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