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nikdorinn [45]
4 years ago
11

How to answer this problem

Mathematics
2 answers:
Julli [10]4 years ago
5 0
There aren´t like term, therefore you have to write the same expression.

Answer: 7u³v³+9s²t

Other example:
7u³+25u³
In this case, we have like terms, therefore: 7u³+25u³=32u³
valina [46]4 years ago
4 0
16s2tu^3v^3 is the answer
You might be interested in
How do you solve this ?
saveliy_v [14]

When given a value of the variable, we replace each instance of the variable in the problem with that number. In this case, the expression becomes:


\frac{3^2 + 3}{3 - 1}


After this, we merely need to simplify the answer.


\frac{9 + 3}{3 - 1}


\frac{12}{2}


Simplifying 12/2 gives us the answer 6.

5 0
3 years ago
Which digit(s) make the solution of the equations the whole number? 5x-496=1.34...
umka21 [38]

Answer:

x≈ 100

Step-by-step explanation:

Given the equation

5x-496=1.34...

We are to find the value of x to the nearest whole number

Add 496 to both sides

5x-496+496 = 1.34+496

5x = 497.34

x = 497.34/5

x = 99.468

x ≈ 100

Hence the value of x to nearest whole number is 100

4 0
3 years ago
Number is 22 round down to
alina1380 [7]

Answer:

22 rounds down to 20 if that is what you are asking

Step-by-step explanation:

You did not finish your question i dont think. 22 DOES round down to 20 though.

3 0
3 years ago
Select the best answer for the question
artcher [175]

Answer:

C

HOWEVER: "Less Than" is usually depicted as a dashed line at the border. and there MUST be an OR between these two equations to include all of the blue area. An "and" there would exclude the area between the edge lines.

Step-by-step explanation:

2x + y < 10

       y < -2x + 10

3x + 2y < 12

       2y < -3x + 12

         y < -1.5x + 6

3 0
3 years ago
Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0
3 years ago
Read 2 more answers
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