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Karo-lina-s [1.5K]

3 years ago

10

What is the symbol for a segment bisector

1 answer:

lutik1710 [3]3 years ago

4 0

This is the symbol for a segment bisector in geometry

Hope this helps!! :)

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The sum of a rational number and an irrational number?

Semenov [28]

Answer:

Is irrational

Step-by-step explanation:

Let $r$ be a rational number, and $i$ be an irrational number. If their sum were rational, say $q$ , then we'd have

$r+i=q \iff i=q-r$

but $q-r$ is the difference between two rational numbers, and thus a rational number. But it also equals $i$ , which is irrational by hypothesis. Since we have a contradiction, we conclude that the sum of a rational and an irrational can't be rational.

3 0

3 years ago

Wich proportion would you set up to change 5 pounds to ounces

Gnesinka [82]

Answer:

80 oz

Step-by-step explanation:

There are 16 ounces in a pound, so:

5 lbs (16 oz/1 lbs)

Multiply the 2 and you get 80 oz.

6 0

2 years ago

Read 2 more answers

What is the slope of the line which passes through (4,5) and (0,1)

kotegsom [21]

Y=x+1

You can solve using slop formula

6 0

3 years ago

SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS

antiseptic1488 [7]

Answer:

$\sf -11+7\sqrt{2}$

Step-by-step explanation:

Given expression:

$\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }$

Rewrite 32 as 16 · 2:

$\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }$

Apply radical rule $\sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }$

As $\sf \sqrt{16}=4$ :

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }$

Multiply by the conjugate:

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }$

$\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}$

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}$

As $\sf \sqrt{2}\sqrt{2}=\sqrt{4}=2$ :

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}$

$\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}$

$\sf \implies \dfrac{11-7\sqrt{2}}{-1}$

$\sf \implies -11+7\sqrt{2}$

7 0

1 year ago

kap26 [50]

Answer:

The root is x = -2

Step-by-step explanation:

1. Add 4 on both sides.

x^2 + 4r + 4 = 0

2. What two numbers, if added together and multiplied together, give 4?

2 and 2.

3. Factor

(x+2)(x+2)=0

4. Solve

x = -2 (There is only one root for this quadratic equation.)

Please give me brainliest is this is right. Than you!

6 0

2 years ago