Answer:
1,3
Step-by-step explanation:
Can’t have 2 of the same X
The answer is: " 10,047.5 " .
_______________________________
Explanation:
________________________________
Given: " x⁴ + 44 + 3.5 " ; and given: "x = 50" ;
we can plug in "50" for "x" ; and solve:
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10⁴ + 44 + 3.5 ;
= 10,000 + 44 + 3.5 ;
= 10,047.5
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Don't you mean 66 divided by eight?
That would equal 8.25, or 8 remainder 2.
if you did mean 8 divided by 66, your answer is not one of your choices.
Answer:
The correct answers are:
A. The Vertical axis should be labelled as the Number of Jars for Each Flavour
B. an interval of 7 could be appropriate
Step-by-step explanation:
A. The number of jars for each flavour is the dependent variable against the flavour type, which is the independent variable, hence it is displayed on the vertical axis to show the height of the bars.
B. since the number of sticks in a jar vary from 0 to 49, dividing 49 by 7 will give 7 without a remainder, hence, an interval of 7 will be ideal for the plot, nd a total of 7 bars will be plotted. Intervals are: 0-7, 8-14, 15-21, 22-28, 29-35, 36-42, 43-49.
Answer:
1716 ;
700 ;
1715 ;
658 ;
1254 ;
792
Step-by-step explanation:
Given that :
Number of members (n) = 13
a. How many ways can a group of seven be chosen to work on a project?
13C7:
Recall :
nCr = n! ÷ (n-r)! r!
13C7 = 13! ÷ (13 - 7)!7!
= 13! ÷ 6! 7!
(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)
1235520 / 720
= 1716
b. Suppose seven team members are women and six are men.
Men = 6 ; women = 7
(i) How many groups of seven can be chosen that contain four women and three men?
(7C4) * (6C3)
Using calculator :
7C4 = 35
6C3 = 20
(35 * 20) = 700
(ii) How many groups of seven can be chosen that contain at least one man?
13C7 - 7C7
7C7 = only women
13C7 = 1716
7C7 = 1
1716 - 1 = 1715
(iii) How many groups of seven can be chosen that contain at most three women?
(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)
Using calculator :
(15 * 35) + (6 * 21) + (1 * 7)
525 + 126 + 7
= 658
c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?
(First in second out) + (second in first out) + (both out)
13 - 2 = 11
11C6 + 11C6 + 11C7
Using calculator :
462 + 462 + 330
= 1254
d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?
Number of ways with both in the group = 11C5
Number of ways with both out of the group = 11C7
11C5 + 11C7
462 + 330
= 792