Here we go!
The quadratic formula: x = [-b ± √(b2<span> - 4ac)]/2a
a = 1 (understood coefficient)
b = 12
c = -13
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![x= \frac{-b\pm \sqrt{b^2-4ac} }{2a} \\ x= \frac{-12\pm \sqrt{12^2-4(1)(-13)} }{2(1)} \\ x= \frac{-12\pm \sqrt{144-(-52)} }{2} \\ x=\frac{-12\pm \sqrt{196} }{2} \\ x=\frac{-12\pm14 }{2}](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D%20%20%5C%5C%20x%3D%20%5Cfrac%7B-12%5Cpm%20%5Csqrt%7B12%5E2-4%281%29%28-13%29%7D%20%7D%7B2%281%29%7D%20%20%5C%5C%20x%3D%20%5Cfrac%7B-12%5Cpm%20%5Csqrt%7B144-%28-52%29%7D%20%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B-12%5Cpm%20%5Csqrt%7B196%7D%20%7D%7B2%7D%20%5C%5C%20%20x%3D%5Cfrac%7B-12%5Cpm14%20%7D%7B2%7D)
Okay, so here, we split into 2 problems. If 14 were positive:
![x=\frac{-12+14 }{2} \\ x= \frac{2}{2} \\ x=1](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-12%2B14%20%7D%7B2%7D%20%5C%5C%20x%3D%20%5Cfrac%7B2%7D%7B2%7D%20%20%5C%5C%20x%3D1)
If 14 were negative:
So,
See the attached figure to better understand the problem
we know that
AM=MD
so
triangle AMD is an isosceles right triangle
therefore
its height is half its width.
Then
AB = (1/2)AD----------Equation 1
Perimeter=2*[AB+AD]=34 in ---------> AB+AD=17-------> Equation 2
I substitute 1 in 2
(1/2)AD +AD = 17
(3/2)AD=17
AD=17*2/3----------> AD=34/3-------> 11 1/3 in
AB=(1/2)AD--------> AB=(1/2)*34/3--------> AB=17/3-------> AB=5 2/3 in
the answers are
AD=11 1/3 inAB = 5 2/3 in
The answer is 2.5/100, which equals 25/1000, and then you would simplify it, and then you would get 5/200, which you would get (after dividing top and bottom by 5)
1/50 is the answer.
Hope this helps, and have a nice day:)
would this be considered rise over run?
Answer:
none
Step-by-step explanation:
not sure but the answer is 40 cause 12-7=5 10x3=30 and 3+2=5 and 5+30+5=40