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Dvinal [7]
3 years ago
5

Suppose you have 20 coins that total $4.00. Some coins are nickels and some are quarters. Which of the following pairs of equati

ons would you use to find out how many of each coin you have?
A. n+q=45n+25q=20
B. n+q=20n+q=4.00
C. n+q=4.00200.5n+0.25q=4.00
D. n+q=205n+25q=400
Mathematics
2 answers:
crimeas [40]3 years ago
5 0
A. n+q=45n+25q=20. That should be the correct answer
daser333 [38]3 years ago
3 0
To find this...we need to see how much the total AMOUNT is. 
N is for  nickels and Q is for Quarters.

n+q=20 would be our first equation. 

We could see which choices have this as the first equation and cross the rest of the others out.

B and D have this...so we are left with those two choices.

<span>n+q=20
</span>
Since we do not know how many nickels and quarters there are, we already know how much each is worth. 

Since we have that info, we can write a second equation.

 5n+25q=4.00

Now their is only one  answer that states this. 

Our final answer is that (D) n+q=20  5n+25q=400 is our answer.
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Total = 300 * [(1.055)^11 -1] / .055 -300
Total = 300 * <span> <span> <span> 1.8020924036  </span> </span> </span> -1 /.055 -300
Total = 300 * <span>.8020924036 / .055 - 300
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Total = <span> <span> <span> 4375.0494741818 </span> </span> </span> -300
Total = <span>4075.05


</span>

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