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Dvinal [7]
3 years ago
5

Suppose you have 20 coins that total $4.00. Some coins are nickels and some are quarters. Which of the following pairs of equati

ons would you use to find out how many of each coin you have?
A. n+q=45n+25q=20
B. n+q=20n+q=4.00
C. n+q=4.00200.5n+0.25q=4.00
D. n+q=205n+25q=400
Mathematics
2 answers:
crimeas [40]3 years ago
5 0
A. n+q=45n+25q=20. That should be the correct answer
daser333 [38]3 years ago
3 0
To find this...we need to see how much the total AMOUNT is. 
N is for  nickels and Q is for Quarters.

n+q=20 would be our first equation. 

We could see which choices have this as the first equation and cross the rest of the others out.

B and D have this...so we are left with those two choices.

<span>n+q=20
</span>
Since we do not know how many nickels and quarters there are, we already know how much each is worth. 

Since we have that info, we can write a second equation.

 5n+25q=4.00

Now their is only one  answer that states this. 

Our final answer is that (D) n+q=20  5n+25q=400 is our answer.
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Answer:

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Drag the tiles to the correct boxes to complete the pairs. Match the systems of equations with their solutions.
Oksanka [162]

Answer:

See explanation for matching pairs

Step-by-step explanation:

Equations

(1)

x - y = 25

2x + 3y = 180  

(2)

2x - 3y = -5

11x + y = 550  

(3)

x - y = 19

-12x + y = 168

Solutions

(-17,-36)

(47, 33)

(51, 26)

Required

Match equations with solutions

(1) x - y = 25 and 2x + 3y = 180

Make x the subject in: x - y = 25

x = 25 + y

Substitute x = 25 + y in 2x + 3y = 180

2(25 + y) + 3y = 180

50 + 2y + 3y = 180

50 + 5y = 180

Collect like terms

5y = 180-50

5y = 130

Solve for y

y =26

Recall that: x = 25 + y

x = 25 + 26

x = 51

So:

(x,y) = (51,26)

(2)  2x - 3y = -5 and 11x + y = 550

Make y the subject in 11x + y = 550

y = 550 - 11x

Substitute y = 550 - 11x in 2x - 3y = -5

2x - 3(550 - 11x) = -5

2x - 1650 + 33x = -5

Collect like terms

2x  + 33x = -5+1650

35x = 1645

Solve for x

x = 47

Solve for y in y = 550 - 11x

y = 550 - 11 * 47

y = 550 - 517

y = 33

So:

(x,y) = (47,33)

(3)

x - y = 19  and -12x + y = 168

Make y the subject in -12x + y = 168

y = 168 + 12x

Substitute y = 168 + 12x in x - y = 19

x - 168 - 12x = 19

Collect like terms

x -12x = 168 + 19

-11x = 187

Solve for x

x = -17

Solve for y in y = 168 + 12x

y =168-12 *17

y =-36

So:

(x,y) = (-17,-36)

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