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3 years ago

Simplify the following questions: 2[y-3(y-5)]

2 answers:

7 0

2(y−3(y−5))=(2)(y+−3y+15)=(2)(y)+(2)(−3y+15)=2y−6y+30=−4y+30

Sauron [17]3 years ago

4 0

The answer would be -4y+30

2[y-3(y-5)]

2y-6(y-5)

2y-6y-30

4y-30

You might be interested in

How does making a frequency table or line plot help you see which value occurs most often in a data set?

klemol [59]

Answer:

A frequency table and a line plot show which value occurs most often. this is done by labeling every value. The person can clearly see the organized layedout numbers in a frequency table or line plot.

Step-by-step explanation:

If you have any questions feel free to ask in the comments.

4 0

2 years ago

If there are:

wolverine [178]

Answer:

total number of marble=22

probability of picking 1 blue marble= 1/22 

 =45×10^-2

probability of getting a green ball= 5/21

 = 238×10^-3

 

4 0

3 years ago

A particular fruit's weights are normally distributed, with a mean of 406 grams and a standard deviation of 27 grams.The heavies

Tom [10]

Given

mean of 406 grams and a standard deviation of 27 grams.

Find

The heaviest 14% of fruits weigh more than how many grams?

Explanation

given

mean = 406 gms

standard deviation = 27 gms

using standard normal table ,

$\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}$

Final Answer

Therefore , The heaviest 14% of fruits weigh more than 435.16 gms

8 0

1 year ago

Solve -3 = x + x + x.

kozerog [31]

-3 = x + x + x
-3 = 3x
-3/3 = x
x = -1

6 0

3 years ago

Read 2 more answers

Numa turma, 5% dos homens e 2% das mulheres tem mais de 1,60m de altura. Por outro lado, 60% dos estudantes são homens. Se um es

Zinaida [17]

Answer:

0.8%

Step-by-step explanation:

Because they are two independent events, the final probability is the product of the probability of each event.

First event:

The complement of a student being male is that he is female.

Therefore, if 60% is male, the remaining 100% is 40%, meaning that 40% of the students are female.

Second event:

If she's taller than 5'4", we're told she has a 2% chance of being a woman.

Therefore the final probability is:

0.4*0.02 = 0.008

That is, the probability that it is female and that it is over 1.6 meters tall is 0.8%.

6 0

3 years ago