Answer:
a) a^6+6a^4b+15a^2b^2+20b^3+15(b^4/a^2)+6(b^5/a^4)+(b/a)^6
b) 20
c) a^6+6a^4+15a^2+20+15/a^2+6/a^4+1/a^6
Step-by-step explanation:
(a+b/a)^6=a^6+6a^5(b/a)+15a^4(b/a)^2+20a^3(b/a)^3+15a^2(b/a)^4+6a(b/a)^5+(b/a)^6
a^6+6a^4b+15a^2b^2+20b^3+15(b^4/a^2)+6(b^5/a^4)+(b/a)^6
b) the coefficient of b^3=20
c) if b=1, the expression is
a^6+6a^4+15a^2+20+15/a^2+6/a^4+1/a^6
Answer:
The mean absolute deviation of the data set is 6
Step-by-step explanation:
To find the mean absolute deviation of the data, start by finding the mean of the data set.
- Find the sum of the data values, and divide the sum by the number of data values.
- Find the absolute value of the difference between each data value and the mean: |data value – mean|.
- Find the sum of the absolute values of the differences.
- Divide the sum of the absolute values of the differences by the number of data values
∵ The data are 68 , 59 , 65 , 77 , 56
- Find their sum
∴ The sum of the data = 68 + 59 + 65 + 77 + 56 = 325
∵ The number of data in the set is 5
- Find the mean by dividing the sum of the data by 5
∴ The mean = 325 ÷ 5 = 65
- Find the absolute difference between the each data and the mean
∵ I68 - 65I = 3
∵ I59 - 65I = 6
∵ I65 - 65I = 0
∵ I77 - 65I = 12
∵ I56 - 65I = 9
- Find the sum of the absolute differences
∵ The sum of the absolute differences = 3 + 6 + 0 + 12 + 9
∴ The sum of the absolute differences = 30
Divide the sum of the absolute differences by 5 to find the mean absolute deviation
∴ The mean absolute deviation = 30 ÷ 5 = 6
The mean absolute deviation of the data set is 6
Answer:
Step-by-step explanation:
The formula for the volume (V) of a sphere is:
V = ⁴/₃πr³
We can use this equation to calculate the radius (r) and from there get the diameter (D).
Answer:
$1,800 is the correct answer.
I would say random placement would have a random out come do you not agree