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3 years ago

What is the solution of the system of equations below?

2 answers:

7 0

2x + 3y = 7
x + y = 3

x = 3 - y

substituting for x,

2(3 - y) + 3y = 7

= 6 - 2y + 3y = 7
6 + y = 7

thus, y = 1

x = 3 - y

= 3 - 1
= 2.

Thus, x = 2 , y = 1

Thus, (2) is correct.

Nostrana [21]3 years ago

3 0

$\begin{cases}2x + 3y = 7 \\ x + y = 3 \ \ / *(-2) \end{cases}\\ \\\begin{cases}2x + 3y = 7 \\ -2x - 2y = -6\end{cases}\\+ \ ------- \\y=1\\ \\2x + 3\cdot1 = 7$

$2x+3=7 \ \ |-3\\ \\ 2x+3-3=7-3\\ \\2x=4 \ \ /:2 \\ \\x=2 \\ \\ \begin{cases} x=2 \\ y=1 \end{cases}$

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3 years ago

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Answer:

B. Obtuse Triangle

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3 years ago

Jena's income is $1600 a month, and she plans to budget 1/3 of her income for rent and 1/8 of her income for groceries. Step 2 o

WARRIOR [948]

Answer:

Jena spends $ 733. 33 on her rent and groceries altogether per month.

Step-by-step explanation:

Jena's total income in a month= $1600

Here , expenditure on rent = (1/3) of her income

So, now one- third of her income $1600 is

= $\frac{1}{3} \times 1600 = 533.33$

or, (1/3) of her salary is $533. 33

Hence, Jena spends $ 533. 33 on her rent monthly.

Now, her expenditure on groceries = (1/8) of her income

So, now one- eighth of her income $1600 is

= $\frac{1}{8} \times 1600 = 200$

or, (1/8) of her salary is $ 200.

Jena spends $ 200. on her groceries monthly.

So, Total expenditure = Expenditure on rent + Expenditure on groceries

= $533. 33 + $200 = $733.33

Hence, Jena spends $ 733. 33 on her rent and groceries altogether per month.

7 0

3 years ago