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3 years ago

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Amy leaves a rest stop at 2 PM traveling west, at 45 miles per hour. Sarah leaves 2 hours later, also traveling west, but at 55

miles per hour. At what time will Sarah catch up with Amy?

2 answers:

Luden [163]3 years ago

4 0

55(t-2) =45t

55t-110 = 45t

-110 = -10t

t = 11 hours

2 pm plus 11 hours = 1 am

Darina [25.2K]3 years ago

3 0

Answer: mathematics, central tendency is the tendency of data values to cluster around some central value. What does a measure of variability tell you about the central tendency of a set of data? ... If the range and IQR are small, the values are clustering around some central value.

Step-by-step explanation:

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The scores of fourth grade students on a mathematics achievement test follow a normal distribution with a mean of 75 and standar

mamaluj [8]

Answer:

The appropriate solution is:

(a) 0.1056

(b) 0

(c) 0.9544

Step-by-step explanation:

The given values are:

Mean,

$\mu = 75$

Standard deviation,

$\sigma = 4$

(a)

⇒ $P(x>80)=1-(x$

$=1-P[\frac{x-\mu}{\sigma}$

$=1-P[\frac{x-\mu}{\sigma}$

$=1-P(z$

By using the table, we get

$=1-0.8944$

$=0.1056$

(b)

According to the question, the values are:

$n$ = 64

$\mu_\bar{x}$ = 75

Now,

⇒ $\sigma_\bar{x}$ = $\frac{\sigma}{\sqrt{n} }$

= $\frac{4}{\sqrt{64} }$

= $\frac{4}{8}$

= $0.5$

⇒ $P(\bar {x} >80 ) = 1 - P(\bar x$

$=1 - P[\frac{(\bar x-\mu_\bar x)}{\sigma \bar x} < \frac{80-75}{0.5} ]$

$=1-P(z$

By using the table, we get

$=1-1$

$=0$

(c)

As we know,

⇒ $\sigma_\bar x$ = $\frac{\sigma}{\sqrt{n} }$

= $\frac{4}{\sqrt{64} }$

= $\frac{4}{8}$

= $0.5$

then,

= $P(74< \bar x$

= $P[\frac{74-75}{0.5} < \frac{\bar x-\mu \bar x}{\sigma \bar x} < \frac{76-75}{0.5} ]$

= $P(-2$

= $P(z$

By using the table, we get

= $0.9772-0.0228$

= $0.9544$

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3 years ago