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2 years ago

How many solutions does an equation have when you isolate the variable and it equals a constant

Mathematics

1 answer:

Olin [163]2 years ago

3 0

There is only one solution since x=0 x cant be many things since the only thing that would make this true is 0

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PLEASE HELP MEEE!!!!!!!!!!!!!!!!!!!!!!!!!!!

Nana76 [90]

Answer:

100,000

Step-by-step explanation:

100,000 x 2 is 200,000

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2 years ago

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A salesman earns 30% commission on the merchandise that he sells last month he sold $600 worth of merchandise how much of commis

romanna [79]

Answer:

$180

Step-by-step explanation:

.3 * 600

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2 years ago

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What is the value of arcsin1/2<br><br> Please show all work thx

almond37 [142]

Answer:

The Answer is 0.785398163 rad

Step-by-step explanation:

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3 years ago

What is the answer to number 8.

Viktor [21]

Its 20. |-2|+4-(-2)×(7). This simplifies to 2+4+(2×7)

4 0

3 years ago

Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact

umka2103 [35]

Solution:

The permutation formula is expressed as

$\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\ \end{gathered}$

The combination formula is expressed as

$\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\ \\ \end{gathered}$

where

$\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}$

Given that 6 objects are taken at a time from 8, this implies that

$\begin{gathered} n=8 \\ r=6 \end{gathered}$

Thus,

Number of permuations:

$\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}$

Number of combinations:

$\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}$

Hence, there are 28 combinations and 20160 permutations.

7 0

6 months ago