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Pepsi [2]
3 years ago
11

What is the slope-intercept form of the function that contains the point (6, 2) and has a slope of 3?

Mathematics
1 answer:
solong [7]3 years ago
7 0
The general formula: y=mx+b

(6,2) ⇒ x=6,y=2
m=3
b=?

2=3*6+b
2=18+b
b=-16

<u>y=3m-16</u>
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Slope Of (5,-5) and (-1,-5)
Alex777 [14]

\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-5}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{5}}}\implies \cfrac{-5+5}{-6}\implies \cfrac{0}{-6}\implies 0

4 0
3 years ago
Find the volume of the cone. Round your answer to the nearest tenth if necessary. Use 3.14 for it.
Korolek [52]

Answer:

452.448cm^3

Step-by-step explanation:

Given data

Height= 25cm

Diamter= 12cm

Radius= 6cm

The expression for the volume of a cone is given as

V= 1/3*πr^2h

Substitute

V= 1/3*3.142*6^2*25

V=  1/3*3.142*36*12

V=  1/3*1357.344

V=452.448cm^3

Hence the volume is 452.448cm^3

8 0
3 years ago
Suppose we have three urns, namely, A B and C. A has 3 black balls and 7 white balls. B has 7 black balls and 13 white balls. C
professor190 [17]

Answer:

a. 11/25

b. 11/25

Step-by-step explanation:

We proceed as follows;

From the question, we have the following information;

Three urns A, B and C contains ( 3 black balls 7 white balls), (7 black balls and 13 white balls) and (12 black balls and 8 white balls) respectively.

Now,

Since events of choosing urn A, B and C are denoted by Ai , i=1, 2, 3

Then , P(A1 + P(A2) +P(A3) =1 ....(1)

And P(A1):P(A2):P(A3) = 1: 2: 2 (given) ....(2)

Let P(A1) = x, then using equation (2)

P(A2) = 2x and P(A3) = 2x

(from the ratio given in the question)

Substituting these values in equation (1), we get

x+ 2x + 2x =1

Or 5x =1

Or x =1/5

So, P(A1) =x =1/5 , ....(3)

P(A2) = 2x= 2/5 and ....(4)

P(A3) = 2x= 2/5 ...(5)

Also urns A, B and C has total balls = 10, 20 , 20 respectively.

Now, if we choose one urn and then pick up 2 balls randomly then;

(a) Probability that the first ball is black

=P(A1)×P(Back ball from urn A) +P(A2)×P(Black ball from urn B) + P(A3)×P(Black ball from urn C)

= (1/5)×(3/10) + (2/5)×(7/20) + (2/5)×(12/20)

= (3/50) + (7/50) + (12/50)

=22/50

=11/25

(b) The Probability that the first ball is black given that the second ball is white is same as the probability that first ball is black (11/25). This is because the event of picking of first ball is independent of the event of picking of second ball.

Although the event picking of the second ball is dependent on the event of picking the first ball.

Hence, probability that the first ball is black given that the second ball is white is 11/25

​​

8 0
3 years ago
What is a relative frequency?
SVETLANKA909090 [29]

Answer:

"A relative frequency distribution is a table that shows the relative frequency for all categories as shown below. Notice that the sum of the relative frequencies is always equal to 1. The percentage of a category is found by multiplying the relative frequency of that category by 100."

Credits To: statistics-made-easy.com › what-is-relative-frequency

4 0
2 years ago
MATH PLEASEEE I WILL MARK YOU BRAINLIEST!!
USPshnik [31]

Answer:

The second

Step-by-step explanation:

is the correct equation

4 0
3 years ago
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