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Pepsi [2]
3 years ago
11

What is the slope-intercept form of the function that contains the point (6, 2) and has a slope of 3?

Mathematics
1 answer:
solong [7]3 years ago
7 0
The general formula: y=mx+b

(6,2) ⇒ x=6,y=2
m=3
b=?

2=3*6+b
2=18+b
b=-16

<u>y=3m-16</u>
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What is the slope and y intercept of the points (4,8) and (20,24)​
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Write an equation of the line that passes through (2,5) and is parallel to the line 2y = 3x + 10.
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Answer:

y = 3/2x - 8  hope I helped

Step-by-step explanation:

To find the equation of a line, we need a point and a slope. We're given a point, and we can easily get the slope. First let's solve 2y = 3x + 10 for y so we can get the slope (recall that y = mx + b is the slope-intercept form, and m is your slope).

2y = 3x + 10  --> almost there already, just divide everything by 2 to get y by itself.

y = 3/2x + 5 --> now you have it in the y=mx + b form, so your slope is 3/2

They asked for the parallel line, remember parallel lines have the same slope, therefore you use the same slope.

Now we know that our slope is m = 3/2 and our point is (2, -5)

You can always find the equation of a line using the Point-Slope Formula:

y - y1 = m(x - x1)    --> our x1 is 2 and our y1 is -5, and slope is 3/2

y - (-5) = 3/2(x - 2)   --> Be careful when you have minus a negative number, like we do here. It becomes:

y + 5 = 3/2(x - 2)  --> now distribute the 3/2

y + 5 = 3/2x - 6/2

y + 5 = 3/2x - 3  --> now we can subtract 5 from both sides to get it into slope intercept form.

y = 3/2x - 8  --> This is the equation of a line that is parallel to 2y=3x+10 & passes through (2, -5)

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