Ask question

Ask question

All categories

3 years ago

7

The length of a rectangular rug is 4 feet more than the width. If the area of the rug is 252 square feet, find the dimensions of

the rug.

1 answer:

Allushta [10]3 years ago

6 0

4 x ? = 252

Do the opposite of multiplication.

252 ÷ 4 = ?

? = 63.

Hope this Helps! :)

You might be interested in

Graph the linear equation find three points that solve the equation then plot on the graph -3y=-x-7

Ira Lisetskai [31]

$- 3y = - x - 7 \\ y = \frac{1}{3} x + \frac{7}{3}$
$\binom{ - 1}{2} \: \: \: \: \: \: \binom{2}{3} \: \: \: \: \: \: \binom{5}{4}$
this is the line

7 0

3 years ago

Read 2 more answers

Alexus [3.1K]

Answer:

C. $8483

Step-by-step explanation:

To find the coffee sales, we plug in the value of x as 34 into y = 60x + 6443.

$y=60(34)+6443$
$y=2040+6443$
$y=8483$

Therefore, the answer is C. $8483.00.

3 0

2 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

Help i made it worth a lot of points

raketka [301]

Answer:

36x^6/y^10

Step-by-step explanation:

First evaluate the parentheses, 6x^3 x 6x^3 = 36x^6

y^5 x y^5 = y^10 ; remember m^k x m^r = m^k+r

final answer should be 36x^6/y^10

hope this helps :')

4 0

2 years ago

Read 2 more answers

vfiekz [6]

54 percent

You add the two together to get 39, then divide 21 by 39. This gives you 0.538, which turns into 54%

7 0

3 years ago