Answer:
6 miles
Step-by-step explanation:
The formula to find the hypotenuse of a right triangle is as follows,

The line is supposed to be longer on the rooting but it won't go any longer so we just have to make do.
Anyways, a is 1 side length and b is the other. Doesn't matter which one you make b or a.
Now you just plug in and solve
(that's after you square it)
add them

simplify
5.83095189485
you can just stop at the hundredths place
5.83
You can estimate that it's about 6
and 6 is your answer
I believe it is neither
For one if you plug in either of them the first one is going to be negative 3. But if you use the second one then your answer would be -3+12= -10 but -3+12 is 9 so I would go with neither because I don't see how it's both
the correct answer is B
"ice cream at -3 degrees C is cooler than ice cream at 1 degree C"
-3 is smaller than 1
-3 < 1
Answer:
2.0 seconds
Step-by-step explanation:
<u>Given quadratic functions</u>:

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

<u>Factor</u> the quadratic:

Apply the <u>zero-product property</u> to solve for x:


Therefore, the balloons collided at 1 second and 2 seconds.
To find at which time the highest point of collision occured, substitute both values of x into one of the functions:


Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.
Learn more about quadratic systems of equations here:
brainly.com/question/27930827
Answer:
20 trail markers
Step-by-step explanation: I would appreciate a brainiiest