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3 years ago

The quotient of a number and -2

Mathematics

2 answers:

Paraphin [41]3 years ago

7 0

-2 = n/-2 or = -n/2 is your answer!!!!!

PLZ MARK BRAINLEST PLZ!!!!!!!!

MA_775_DIABLO [31]3 years ago

3 0

The quotient of a number and -2 = n/-2 or = -n/2

Hope that helps.

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How do i write a Word phrase to represent the numerical expresion 5+(17-8)

Lerok [7]

Answer:

If i was to read this out loud, i would say: 5 plus the quantity of 17 minus 8.

Step-by-step explanation:

5 + (17-8)

Parenthesis need to be done first! That is why you need to say 'the quantity of...' You also have to add 5 to it all, and you might as well do it before 'the quantity of...' becuz it comes before it in the numerical expression.

YAY! ! ! YOU GOT IT!!! =)

8 0

3 years ago

Use the function below to find F(3). F(x) = 4(1/3)^x

aalyn [17]

Answer:

4/27

Step-by-step explanation:

F(x) = 4(1/3)^x

Let x =3

F(3) = 4(1/3)^3

Exponents first

F(3) = 4 * 1/27

Then multiply

f(3) = 4/27

6 0

2 years ago

Read 2 more answers

Toblas has a job walting tables where he earns a certain amount every month and an additional amount per table, according to the

Rom4ik [11]

Answer:

Does it have a graph of any numbers in your question?

Step-by-step explanation:

7 0

2 years ago

A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January

Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that $p = 0.23$

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789$

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084$

$P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181$

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343$

$P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225$

$P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439$

$P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109$

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116$

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

$E(X) = np = 10*0.23 = 2.3$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.23*0.77} = 1.33$

The expected number is 2.3 and the standard deviation is 1.33.

5 0

3 years ago

What is the period of the graph y=1/2sin (pix)+3? A- 3 B- 1/2 C-pi D-2

dimaraw [331]

The period is 2.

Normally the period of sin(x) is 2pi, but the pi inside the sin(pix) is a horizontal compression by a factor of 1/pi. So 2pi·1/pi = 2

The "1/2" and "+3" do not impact the period. Those just impact the amplitude (vertical aspect) of the graph.

3 0

3 years ago