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TiliK225 [7]
3 years ago
15

Two positive numbers x and y, with the maximum value 4, add up to 5. what is the difference between the maximum and minimum valu

e of the product x^2y^3.
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
6 0

Answer:

1023

Step-by-step explanation:

Positive numbers are numbers that are greater than 0.

As maximum value of numbers x and y is 4,

x\leq 4,y\leq 4      ....(i)

So,

x^2y^3\leq 4^2 4^3=1024

So, maximum value of the product x^2y^3 is 1024.

Also, its given that sum of numbers x and y is 5, so x+y=5   ...(ii)

On using equations (i) and (ii), we get

1\leq x,1\leq y

So,

1\leq x^2y^3

Therefore, minimum value of the product is 1.

Difference between the maximum and minimum value of the product =  maximum value of the product x^2y^3 - minimum value of the product

=1024 - 1 = 1023

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Triangles abc, dbe, and fbg are all symmetric about the y-axis. what are the coordinates of the centroid?
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Answer:

The coordinates of the centroid are (0, 5)

Step-by-step explanation:

The coordinates of the centroid of a triangle whose vertices (x1, y1), (x2, y2), and (x3, y3) are (\frac{x1+x2+x3}{3} , \frac{y1+y2+y3}{3})

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∴ The centroid = (\frac{-20+0+20}{3} , \frac{0+15+0}{3}) = (\frac{0}{3} , \frac{15}{3}) = (0, 5)

∴ The coordinates of the centroid of Δ ABC are (0, 5)

In Δ DBE

∵ D = (-15, 0), B = (0, 15), E = (15, 0)

∴ x1 = -15, x2 = 0, x3 = 15

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = (\frac{-15+0+15}{3} , \frac{0+15+0}{3}) = (\frac{0}{3} , \frac{15}{3}) = (0, 5)

∴ The coordinates of the centroid of Δ DBE are (0, 5)

In Δ FBG

∵ F = (-5, 0), B = (0, 15), G = (5, 0)

∴ x1 = -5, x2 = 0, x3 = 5

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = (\frac{-5+0+5}{3} , \frac{0+15+0}{3}) = (\frac{0}{3} , \frac{15}{3}) = (0, 5)

∴ The coordinates of the centroid of Δ FBG are (0, 5)

∵ The three triangles are symmetric about the y-axis

→ That means they have the same centroid and it lies on the y-axis

∴ The coordinates of the centroid are (0, 5)

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(b)

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