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77julia77 [94]
3 years ago
8

Why there must be at least two lines on any given plane

Mathematics
1 answer:
ratelena [41]3 years ago
7 0
Although theoretically there are infinite lines in space and in a plane, too, at least three non collinear points are necessary to define a plane. Two intersecting lines will therefore be necessary to define it (two points create a line); these intersecting lines are the ones to help define coordinates (x,y).
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Can someone help me with these questions I want to make sure I got them right ​
Andrej [43]

9514 1404 393

Answer:

  1. 14/9
  2. -3.6
  3. 5/4
  4. 11/2, 7/8, 5/18

Step-by-step explanation:

1. n = (11/6 -2/3)(4/3) = (7/6)(4/3) = 14/9

__

2. x = (9.82 -28.18)/5.1 = -3.6

__

3. y = 3/2 -1/4 = 5/4

__

4a. t = 2(3 -1/4) = 11/2

4b. y = (1/5 +1/2)(5/4) = ((2+5)/10)(5/4) = 7/8

4c. x = (11/3 -2)/6 = (5/3)(1/6) = 5/18

3 0
2 years ago
true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp
Goshia [24]

Answer:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

6 0
3 years ago
I will make you brainliest pls help me
Licemer1 [7]

1) 8

2) 6(5x+2y) factor out greatest common factor

3) 10.8 just move over decimal two places to the left.

4) 30t=150? Then t=5kg Im not sure what the last one is asking, but I’m assuming it’s to solve for t.

4 0
2 years ago
Given:<br>AC – AR<br>&lt;1 = &lt;2<br>Prove:<br>&lt;3 =&lt;4<br><br>​
Katena32 [7]

Answer:

ΔCTA ≅ ΔDRA

Step-by-step explanation:

Triangles CTA and DRA are congruent by ASA postulate. This is because:

  • ∠1 ≅ ∠2 (given)
  • AC ≅ AR (given)
  • ∠A is the same for both triangles (they are opposite angles)

Then, correspondent angles and sides are congruent, for example, ∠3 ≅ ∠4

8 0
3 years ago
Which equations represent the line that is parallel to 2x-7y=9 and passes through the point
almond37 [142]

Answer:

e. 2x - 7y = 31.

Step-by-step explanation:

If you want a line parallel to the equation, the line must have the same slope.

2x - 7y = 9

-7y = -2x + 9

y = 2/7x - 9/7

You are looking for a line where the slope is 2/7.

a. Slope is 7/2.

b. Slope is -7/2.

c. Slope is 7/2.

d. Slope is...

y + 2 = 3/4x + 3

y = 3/4x + 1

Slope is 3/4.

e. Slope is -2/-7, which is 2/7. Just make sure to check whether it passes through (5, -3) by substituting those points into the equation.

2 * 5 - 7 * -3 = 31

10 --21 = 31

10 + 21 = 31

And there's your answer: e.

Hope this helps!

4 0
3 years ago
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