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3 years ago

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The average polar bear weights 1,200 pounds.the average grizzly bear weights 800 pounds.the average black bear weights 400 pound

s.the average polar bear weights how many times more than the average black bear?

1 answer:

Sonja [21]3 years ago

6 0

Just subtract so 1,200-400=800 pounds

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2. Three points of a parallelogram are (4, 3), (-4, 3), and (2, 3). Find the coordinates of the 4th point to complete the parall

antiseptic1488 [7]

Parallelograms have equal and parallel opposite sides

<em>The coordinates of the 4th point is (-2,3)</em>

Let the parallelogram be ABCD, such that:

$A = (4,3)$

$B =(-4,3)$

$C = (2,3)$

A and B have the same y-coordinates, while their x-coordinates are additive inverse

This means that:

The y-coordinates of point C and point D will be the same, while their x-coordinates will be additive inverse.

<u>For point C</u>

We have:

$x = 2$

$y = 3$

<u>For point D</u>

The coordinates would be:

$x =- 2$

$y = 3$

Hence, the coordinates of D is (-2,3)

Read more about parallelograms at:

brainly.com/question/9680084

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2 years ago

Find the value of tan θ for the angle shown. A line is drawn from the origin through the point square root of thirty-three comma

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If you draw this triangle on a graph as described, tan theta is -4(square root)33/33

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A store finds that its sales revenue changes at a rate given by S'(t) = −30t2 + 420t dollars per day where t is the number of da

allochka39001 [22]

Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation $S'(t)= -30t^{2} + 420t$ . The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

$\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\ S(t)= -10t^{3} +210t^{2} \\$

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

$Given\ S(t) = -10t^{3} + 210t^{2}$

$S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860$

Total sales = S(7) - S(0)

= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

To get S(14);

$S(14) = -10(14)^{3} + 210(14)^{2}\\S(14) = -27,440+41,160\\S(14) = 13,720$

The total sales for the second week after campaign ends = 13,720 - 6,860

= $6,860

8 0

3 years ago