Answer:
tell martha to buy huwei matebook x 2020 , its a good one
Step-by-step explanation:
No
Given 3 sides of a triangle, the sum of any 2 sides must be greater than the third side.
Consider the 3 given sides 1, 7 and 11
7 + 11 = 18 > 1
1 + 11 = 12 > 7
1 + 7 < 11 ⇒ not valid
Hence these sides do not form a triangle
The correct answer is C. So, lets go first to the equations that determine the volume of these solids. For the cylinder, that is simple; pi*r*r*h where r is the radius, h is the height and pi is the constant 3.14. For the cone, it is not easy to derive but one gets that the formula is:
![\frac{ \pi*r^2*h}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Cpi%2Ar%5E2%2Ah%7D%7B3%7D)
.
We notice thus that
![V_{cyl}=\pi*r^2*h=3V_{cone}](https://tex.z-dn.net/?f=V_%7Bcyl%7D%3D%5Cpi%2Ar%5E2%2Ah%3D3V_%7Bcone%7D)
. That holds irrespective of their radius or height; we only need to know that the heights and radii of the two objects are the same. Now, we have thus that:
![\frac{V_{Cyl}}{V_{Cone} } =1/3](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7BCyl%7D%7D%7BV_%7BCone%7D%20%7D%20%3D1%2F3)
.
We can check if this holds for Jared's statement; 1178/4712=0.25=1/4. So, it does not hold and thus Jared's statement is incorrect.
Answer:
o.25 or (2
Step-by-step explanation:
<em>Rearrange unknown terms to the left side of the equation</em>
![\boldsymbol{\sf{ 9x > 50.4-9 \ \ \longmapsto \ \ \ [Subtract]}}](https://tex.z-dn.net/?f=%5Cboldsymbol%7B%5Csf%7B%20%209x%20%3E%2050.4-9%20%5C%20%5C%20%5Clongmapsto%20%5C%20%5C%20%5C%20%5BSubtract%5D%7D%7D)
<em>Calculate the sum or difference.</em>
![\boldsymbol{\sf{9x > 41.4 }}](https://tex.z-dn.net/?f=%5Cboldsymbol%7B%5Csf%7B9x%20%3E%2041.4%20%7D%7D)
<em>Convert decimal to fraction.</em>
![\boldsymbol{\sf{9x > \dfrac{414}{10} }}](https://tex.z-dn.net/?f=%5Cboldsymbol%7B%5Csf%7B9x%20%3E%20%5Cdfrac%7B414%7D%7B10%7D%20%20%7D%7D)
<em>Reduce the greatest common factor for both sides of the inequality.</em>
<em> </em>![\boldsymbol{\sf{x > \dfrac{46}{10} }}](https://tex.z-dn.net/?f=%5Cboldsymbol%7B%5Csf%7Bx%20%3E%20%5Cdfrac%7B46%7D%7B10%7D%20%20%7D%7D)
<em>Reduce the fraction</em>
![\red{ \boxed{\boldsymbol{\sf{\blue{ Answer \ \ \longmapsto \ \ x > \dfrac{23}{5} }}}}}](https://tex.z-dn.net/?f=%5Cred%7B%20%5Cboxed%7B%5Cboldsymbol%7B%5Csf%7B%5Cblue%7B%20Answer%20%5C%20%5C%20%5Clongmapsto%20%5C%20%5C%20x%20%3E%20%5Cdfrac%7B23%7D%7B5%7D%20%20%7D%7D%7D%7D%7D)