Snails are natural decomposers
Here is the answer of the given question above.
Often times, non-human life in an urban ecosystem is more disturbed in a way that changes happen rapidly, such as the soil and plant cover and temperature and water availability. In this kind of ecosystem, there is no stability and sustainability. On the other hand, in an undeveloped forest ecosystem, plants play a major role and that, the lives in this kind of ecosystem is undisturbed, making it more ideal for many animals to live. Hope this answer helps.
The answer is step 3. Nerve impulse on a muscle cell induces release of calcium ions
Steps of a muscle contraction are:
1. Nerve impulse travels down the axon and causes a release of acetylcholine.
2. Acetylcholine binds to the receptor of a muscle cell.
3. Nerve impulse on a muscle cell induces a release of calcium ions.
4. Calcium ions induce exposing of myosin to actin.
5. Sliding of actin filaments past myosin filaments.
6. The muscle contract.
I believe the answer is, Sea of Tranquility.
<u>Answer</u>:
- The possible genotypes of the children are Hh and hh.
- The probability of genotype Hh = 1/2
- The probability of genotype hh = 1/2
<u>Explanation</u>:
- <em>Autosomal genes</em> are the genes present on any of the chromosomes except the sex chromosomes.
- An autosomal recessive mutation is the mutation in an autosomal gene which only expresses itself in the phenotype in homozygous condition and affects both males and female equally.
- For the given question, let the autosomal gene be represented by H (dominant) and h (recessive)
- According to the question,
Since the <em>mother</em> is homozygous her genotype would be hh and the <em>father</em> is heterozygous so his genotype would be Hh.
The following cross is made to know the genotypes of the children :
hh X Hh--------> Hh Hh hh hh
So the <em>possible genotypes of the children are Hh and hh as shown in the cross. </em>
Note : An image is attached representing the cross in a Punnett square.
- The probability of an event = No. of favourable outcomes/total no. of outcomes
The probability of occurrence of genotype Hh would be = 2/4 = 1/2
Similarly, the probability of occurrence of genotype hh would be 2/4 = 1/2