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Andrei [34K]
4 years ago
7

1. How many times do normal somatic cells reproduce (undergo mitosis)? How do they know when

Biology
1 answer:
Dvinal [7]4 years ago
6 0

Answer:

Explanation

Usually, cells will take between 5 and 6 hours to complete S phase. G2 is shorter, lasting only 3 to 4 hours in most cells. In sum, then, interphase generally takes between 18 and 20 hours. Mitosis, during which the cell makes preparations for and completes cell division only takes about 2 hours.

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Read 2 more answers
A couple plans to have a child. the mother is homozygous for an autosomal recessive mutation. the father is heterozygous for the
adoni [48]

<u>Answer</u>:

  • The possible genotypes of the children are Hh and hh.
  • The probability of genotype Hh = 1/2
  • The probability of genotype hh = 1/2

<u>Explanation</u>:

  • <em>Autosomal genes</em> are the genes present on any of the chromosomes except the sex chromosomes.
  • An autosomal recessive mutation is the mutation in an autosomal gene which only expresses itself in the phenotype in homozygous condition and affects both males and female equally.
  • For the given question, let the autosomal gene be represented by H (dominant) and h (recessive)
  • According to the question,

Since the <em>mother</em> is homozygous her genotype would be hh and the <em>father</em> is heterozygous so his genotype would be Hh.

The following cross is made to know the genotypes of the children :

hh X Hh--------> Hh Hh hh hh

So the <em>possible genotypes of the children are Hh and hh as shown in the cross. </em>

Note : An image is attached representing the cross in a Punnett square.

  • The probability of an event = No. of favourable outcomes/total no. of outcomes

The probability of occurrence of genotype Hh would be = 2/4 = 1/2

Similarly, the probability of occurrence of genotype hh would be 2/4 = 1/2



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