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DENIUS [597]
4 years ago
10

Help? how can I solve this problem?????

Mathematics
1 answer:
Lerok [7]4 years ago
4 0
A:<
b:>
c:<
...........
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What is 3x + 9 = 2.5x + 14?
Rus_ich [418]

3x+9=2.5x+14. =>

0.5x=5 => x=10.

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1. What is happening from the Original to Step 1? *
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Answer:

distribution

combine like terms/simplifying

subtraction

division

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3r+n^2-r+5n= write in simplest form.
Zinaida [17]
2r+5n^3 is the answer
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4 years ago
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Suppose the large number of auto accidents in a small town results in new legislation that requires all citizens of the town to
tangare [24]

Answer:

a. decrease

b. recklessly

c. increase

Step-by-step explanation:

Suppose the large number of auto accidents in a small town results in new legislation that requires all citizens of the town to install new anti-lock brakes on their cars. These new brakes cut the time it takes a car to stop by 50%, allowing drivers to avoid collisions with other cars and pedestrians more easily. The new brakes <u>decrease</u> the probability that a vehicle will collide with another vehicle but also give drivers an incentive to drive more <u>recklessly</u> which could potentially <u>i</u><u>ncrease</u> the number of car accidents.

Because the new brakes cut the time it takes a car to stop by 50%, allowing drivers to avoid collision easily, drivers may become confident and drive recklessly which could potentially increase the number of car accidents

5 0
3 years ago
An equation for the depreciation of a car is given by y=A(1-r)t where y=current value of the car.A=original cost r=rate of depre
Ann [662]
<h3>Answer: Approximately 6.58 years old</h3>

The more accurate value is 6.57881347896059, which you can round however you need. I picked two decimal places.

==================================================

Explanation:

Let's pick a starting value of the car. It doesn't matter what the starting value, but it might help make the problem easier. Let's say A = 1000. Half of that is 1000/2 = 500.

So we want to find out how long it takes for the car's value to go from $1000 to $500 if it depreciates 10% per year.

The value of r is r = 0.10 as its the decimal form of 10%

t is the unknown number of years we want to solve for

---------------------------

y = A(1 - r)^t

500 = 1000(1 - 0.1)^t

500 = 1000(0.9)^t

1000(0.9)^t = 500

0.9^t = 500/1000

0.9^t = 0.5

log( 0.9^t ) = log( 0.5 )

t*log( 0.9 ) = log( 0.5 )

t = log( 0.5 )/log( 0.9 )

t = 6.57881347896059

Note the use of logs to help us isolate the exponent.

6 0
3 years ago
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