The answer is B becuase if u take the reciplericle by the antiretroviral you would get B
![\bf \begin{array}{|cl|ll} \cline{1-2} term&value\\ \cline{1-2} f(1)&\\ f(2)&\\ f(3)&7\\ f(4)&7r\\ f(5)&7rr\\ &252\\ \cline{1-2} \end{array}\qquad \qquad 7rr=252\implies 7r^2=252\implies r^2=\cfrac{252}{7} \\\\\\ r^2=36\implies r=\sqrt{36}\implies r=6 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|cl|ll} \cline{1-2} term&value\\ \cline{1-2} f(1)&\stackrel{\frac{7}{6}\div 6}{\cfrac{7}{36}}\\ &\\ f(2)&\stackrel{7\div 6}{\cfrac{7}{6}}\\ &\\ f(3)&7\\ f(4)&42\\ f(5)&252\\ f(6)&1512\\ \cline{1-2} \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Ccl%7Cll%7D%20%5Ccline%7B1-2%7D%20term%26value%5C%5C%20%5Ccline%7B1-2%7D%20f%281%29%26%5C%5C%20f%282%29%26%5C%5C%20f%283%29%267%5C%5C%20f%284%29%267r%5C%5C%20f%285%29%267rr%5C%5C%20%26252%5C%5C%20%5Ccline%7B1-2%7D%20%5Cend%7Barray%7D%5Cqquad%20%5Cqquad%207rr%3D252%5Cimplies%207r%5E2%3D252%5Cimplies%20r%5E2%3D%5Ccfrac%7B252%7D%7B7%7D%20%5C%5C%5C%5C%5C%5C%20r%5E2%3D36%5Cimplies%20r%3D%5Csqrt%7B36%7D%5Cimplies%20r%3D6%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Ccl%7Cll%7D%20%5Ccline%7B1-2%7D%20term%26value%5C%5C%20%5Ccline%7B1-2%7D%20f%281%29%26%5Cstackrel%7B%5Cfrac%7B7%7D%7B6%7D%5Cdiv%206%7D%7B%5Ccfrac%7B7%7D%7B36%7D%7D%5C%5C%20%26%5C%5C%20f%282%29%26%5Cstackrel%7B7%5Cdiv%206%7D%7B%5Ccfrac%7B7%7D%7B6%7D%7D%5C%5C%20%26%5C%5C%20f%283%29%267%5C%5C%20f%284%29%2642%5C%5C%20f%285%29%26252%5C%5C%20f%286%29%261512%5C%5C%20%5Ccline%7B1-2%7D%20%5Cend%7Barray%7D)
notice, once we know what the common factor "r" is, from the 3rd term we can simply multiply it by "r" to get the next term, and divide the 3rd term by "r" in order to get the previous term, namely the 2nd term, and then divide the 2nd by "r" to get the 1st one.
Answer: No
Step-by-step explanation:
2.7 + 3.5 is not greater than 9.8.
Answer: 0.8413
Step-by-step explanation:
population mean = 3
population variance = 0.03
sd (standard deviation) = √0.03
Let x = sample mean
x has a mean of 3 and sd of √0.03/√3 = √0.01 = 0.1
And we can aprox the sample mean distribution using a normal distribution
Note: this approximation maybe is not so good (n = 3)
with mean = 3 and sd = 0.1
z = (x-3)/0.1 has a standard normal distribution
P(x<3.1) = P(z<(3.1-3)/0.1) = P(z<1) =0.8413
Answer:
13
Step-by-step explanation:
Please mark brainlliest.
