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2 years ago

What is the strongest factor influencing migration selectivity?

1 answer:

3 0

I would go with the answer E). Just because slavery ended years ago doesn't mean that's its still over even to this day, it use to be about gender as well back than where women couldn't vote but no one cares about that today, the things people care about is race because as the famous quote someone said, humans hate what they don't understand, so most races don't understand why people are all different, so they want to hate them since they don't understand and also get higher authority as well, but to get back to topic race is the most common thing today that encourages people to leave and migrate cause they might not feel welcome.

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1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a NET DECREASE of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.

8 0

1 year ago

Photojournalism and stock photography are essentially the same. Select one: True False

ale4655 [162]

Answer:

False.

Explanation:

If they were the same, they wouldn't have diff names.

4 0

2 years ago

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When driving a manual how do u shift

ziro4ka [17]

B: Press the clutch then take out the gear

7 0

3 years ago

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Why is it when everyone i have something good in my life , it gets destroyed ?

hodyreva [135]

Maybe it not meant to be or it complicated

5 0

2 years ago

Okay so im watching this video on apushreview.com and Im not sure if im suppose to be writing everything in the video or just un

Black_prince [1.1K]

So are familiar with civilization adaption?
Are you familiar with emergence?
Google these two and read all you can in order to know the maximum of the begining of any society.

3 0

2 years ago