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4 years ago

30% of what number is 70

Mathematics

1 answer:

katrin2010 [14]4 years ago

6 0

233 1/3

you start with .3x = 70, as this is the sentence given, solving for x.
divide both sides by .3, and you get x

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Find the exact circumference of a circle with an area equal to 36 sq. in.

DochEvi [55]

The area of the circle is determined through the equation,
A = πr²
Plug in the value of area
36 in² = πr² ; r = 3.385 in
The formula for the circumference of the circle is,
C = 2πr
Substitute the value of radius,
C = 2π(3.385 in) = 6.77π in
Thus, the circumference of the circle is 6.77π inches.

8 0

4 years ago

Read 2 more answers

Prove, Cosec2A + cot2A = cotA

elena-s [515]

Proved

Step-by-step explanation:

Cosec2A + cot2A = cotA

On Left hand-side

$Cosec2A + cot2A = \frac{1}{sin2A} +\frac{cos2A}{sin2A} \\\\\\$

$=\frac{1}{2sinAcosA} +\frac{2cos^2A-1}{2sinAcosA}$

$\frac{1+2cos^2A-1}{2sinAcosA} \\\\\\=\frac{2cos^22A}{2sinAcosA} \\\\=\frac{cosA}{sinA} \\\\\\=cotA$

Learn More

Trigonometric ratios: brainly.com/question/12462203

Keywords: Trigonometeric

#LearnwithBrainly

8 0

3 years ago

Every time Megan takes a sip of water, the level of the water in her glass goes down 2 inches. Which shows the correct way to fi

Dvinal [7]

Answer:

It changes 3 inches

Step-by-step explanation:

Because every time she takes a sip it goes down, I can’t really explain it good but it changes 3 inches as she took 3 sips of water.

7 0

3 years ago

Read 2 more answers

Calculate the total area of the shaded region.

LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

$\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}$

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

$\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill$

$\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}$

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2 years ago

What is the slope of this line

GenaCL600 [577]

The answer can be found by found ride over run so 4/2 or 2/1=2

5 0

3 years ago