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Ipatiy [6.2K]
3 years ago
10

There are 32 forwards and 80 guards in Leo's basketball league.

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
4 0
The greatest common factor is the product of shared primes of the numbers prime factorizations.

32=2*2*2*2*2, 80=2*2*2*2*5  So the GCF is 2*2*2*2=16

So there will be 16 teams with 2 forwards and 5 guards each.
ziro4ka [17]3 years ago
4 0

Answer:

32

Step-by-step explanation:

i did it

You might be interested in
Evaluate W - X if w = 18 and x = 6.<br> Giving BRIANLIEST
xenn [34]

Answer:

12

Step-by-step explanation:

18 -6

12

Hope that this helps you and have a great day :)

5 0
3 years ago
What is the equation of the line that passes through the point (4, 12) and has a y-intercept of -2?
natima [27]

Answer:

The answer is D.

Step-by-step explanation:

:DDDDDDDDD

4 0
3 years ago
Write 3x^2-18x-6 in vertex form
Vedmedyk [2.9K]
The standard form of a quadratic equation is \displaystyle{ y=ax^2+bx+c, while the vertex form is:

                      y=a(x-h)^2+k, where (h, k) is the vertex of the parabola.

What we want is to write \displaystyle{ y=3x^2-18x-6 as y=a(x-h)^2+k

First, we note that all the three terms have a factor of 3, so we factorize it and write:

\displaystyle{ y=3(x^2-6x-2).


Second, we notice that x^2-6x are the terms produced by (x-3)^2=x^2-6x+9, without the 9. So we can write:

x^2-6x=(x-3)^2-9, and substituting in \displaystyle{ y=3(x^2-6x-2) we have:

\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11].

Finally, distributing 3 over the two terms in the brackets we have:

y=3[x-3]^2-33.


Answer: y=3(x-3)^2-33
6 0
3 years ago
A parallelogram has a base of 12 meters and a height of 1.5 meters. What is its area? ​
rusak2 [61]

Answer:

18

Step-by-step explanation:

12×1.5=18

its the same formula with rectangle cz if you combine both right angled triangle side its become a rectangle

4 0
3 years ago
A boat sails on a bearing of 77 degrees for 135 miles and then turns and sails 207 miles on a bearing of 192 degrees. Find the d
Andrew [12]

Answer:

193.53 miles

Step-by-step explanation:

Please see the diagram for understanding of how the angles were derived,

Applying Alternate Angles, ABO =77 degrees

The bearing from B to C is 192=180+12 degrees

Subtracting 12 from 77, we obtain the angle at B as 65 degrees.

We want to determine the boat's distance from its starting point.

In the diagram, this is the line AC.

Applying Law of Cosines:

b^2=a^2+c^2-2acCosB\\b^2=207^2+135^2-2(207)(135)Cos65^\circ\\b^2=37453.8654\\b=\sqrt{37453.8654} \\b=193.53\: miles

The distance of the boat from its starting point is 193.53 miles (correct to 2 decimal places).

6 0
3 years ago
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