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muminat
3 years ago
13

at 7a.m. the outside temperature was -3 Fahrenheit. By noon, the temperature was 10 Fahrenheit. What was the change in temperatu

re from 7 a.m. to noon?
Mathematics
2 answers:
vodka [1.7K]3 years ago
4 0
The temperature change from 7 a.m. to noon is a 13 degree difference. 
Maru [420]3 years ago
3 0

Answer:

Chang 10°© to Fahrenheit

Step-by-step explanation:

You might be interested in
Community Theater Owner A community theater currently sells 200 season tickets at $50 each.
coldgirl [10]

Answer:

200(50) is for the original revenue, and (200 - 10(50 + 5)) is if they increase it once.

4 0
3 years ago
The tree is five times taller than the fence. The fence is two metres tall. How tall is the tree?
yarga [219]

Answer:

10

Step-by-step explanation:

2 x 5

5 0
3 years ago
One side of the trapezoid is 10 Inches. The side parallel to this is twice as long as this side. The height is half as long as t
Mrac [35]
  ___
/ ___ \  Let's imagine a trapezoid looks like this. The two parallel lines would be the top and the bottom lines.

The 10 in. side would be either the top or bottom line. The other parallel line is twice as long, meaning it's 2 times longer. So you multiply 10 in x 2 = 20 in.

The given side length = 10 inches.
Height = half as long, meaning it's half of 10 in. = 5 in.

Formula of a trapezoid = \frac{a+b}{2} x height
Where a and b are bases. The top and bottom of the trapezoid are bases.

Area trapezoid = \frac{10 + 20}{2} x 5 = \frac{30}{2} x 5 = 15 x 5 = 75 in²  <-- area means the unit is squared


4 0
3 years ago
How many ways can 2 Geometry books, 8 Algebra books and 2 Pre-Calculus books be arranged on a shelf if all the books of each res
mariarad [96]

Answer: 2,970

Step-by-step explanation:

The number of ways to arrange n things such that a things are identical , b things are identical , and so on is  \dfrac{n!}{a!\cdot b!\cdot ....} .

As per given , we have

Number of Geometry books = 2

Number of Algebra books = 8

Number of Pre-Calculus books =2

Total books = 2+8+2=12

Then, the number of ways to arrange them : \dfrac{12!}{2!\cdot 8!\cdot 2!}

=\dfrac{12\times11\times10\times9\times8!}{2\times8!\times2}=2970

Hence, the total number of ways to arrange 2 Geometry books, 8 Algebra books and 2 Pre-Calculus books is 2,970.

3 0
3 years ago
suppose there are two types of tickets to a show advance and same day. Advance tickets cost $25 and same dayt costs $15 for one
DiKsa [7]

Answer:

Advanced tickets=30 Day =20

Step-by-step explanation:

Put them into equations:

x=advanced

y=day

x+y=50

25x+15y=1050

to make it simpler re-arrange x+y=50

x=50-y

Then substitute into 25x+15y=1050

25(50-y)+15y=1050

Expand

1250-25y+15y=1050

Rearrange

25y-15y=1250-1050

Work the above out

10y=200

y=20

and then

20+x=50

meaning....

x=30

showing Advanced tickets=30 Day =20

5 0
3 years ago
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