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2 years ago

13

at 7a.m. the outside temperature was -3 Fahrenheit. By noon, the temperature was 10 Fahrenheit. What was the change in temperatu

re from 7 a.m. to noon?

2 answers:

vodka [1.7K]2 years ago

4 0

The temperature change from 7 a.m. to noon is a 13 degree difference.

Maru [420]2 years ago

3 0

Answer:

Chang 10°© to Fahrenheit

Step-by-step explanation:

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Car park algebra question

Svetllana [295]

You did south, north, correctly

but last one

twice north is 2 times (x+48) or 2x+96

so

s=x
n=x+48
c=4x
s+c>2x+96
subsitute s for x and 4x for c
x+4x>2x+96
5x>2x+96
minus 2x both sides
3x>96
divide both sides by 3
x>32
it cannot be equal to 32 so
the minimum value is 33 spaces in south car park

5 0

2 years ago

A square pyramid has a height of 6 units and a volume of 70 units3. If a square prism has the same base area and volume as the s

inysia [295]

Answer:

The height is 2 units

Step-by-step explanation:

Find the area of the base of the square pyramid

we know that

The volume of the square pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the base and H is the height of the pyramid

we have

$H=6\ units$

$V=70\ units^{3}$

substitute in the formula and solve for B

$70=\frac{1}{3}B(6)$

$B=70/2=35\ units^{2}$

step 2

Find the height of the square prism

we know that

The volume of the square prism is equal to

$V=Bh$

where

B is the area of the base and h is the height of the prism

we have

$B=35\ units^{2}$

$V=70\ units^{3}$

substitute in the formula and solve for h

$70=(35)h$

$h=2\ units$

3 0

3 years ago

Read 2 more answers

Match the following rational expressions to their rewritten forms.

Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

$1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}$

And the rewritten forms:

$(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}$

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

$(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}$

So, correct option is 3.

$(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}$

So, correct option is 1.

$(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}$

So, correct option is 2.

$(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}$

So, correct option is 4.

The answer is also attached in the answer area.

7 0

2 years ago

Which expression can be substituted for y in the top equation of the

maria [59]

Answer:

Y=7+3x, x=-3, y=-2

Step-by-step explanation:

3x-5y=1. Equation 1

3x-y=-7. Equation 2

-y=-7-3x isolate for y in equation 2

y=7+3x multiplied by -1 to get positive y

3x-5(7+3x)=1 substitute y value of equation 2 (7+3x) into equation 1

3x-35-15x=1

-12x=36

x=-3

solve for y.

3x-5y=1

3(-3)-5y=1

-9-5y=1

-5y=10

y=-2

6 0

2 years ago

Given that z20 = –2 and z50= – 1, which of the following do you know?

Klio2033 [76]

Answers: #2, 3, 5, 6 are correct

... believe me, I juss did them.

6 0

3 years ago

Read 2 more answers