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3 years ago

Find the distance between (4,2) and (-4,-4)

1 answer:

3 0

Use the distance formula, and plug in values.
$d = \sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1} )^{2}}$
 $d = \sqrt{( -4-4 )^{2}+( -4-2 )^{2}}$
$d = \sqrt{( -8 )^{2}+( -6 )^{2}}$
$d = \sqrt{64+36}$
$d= \sqrt{100}$

Therefore, the distance is equal to "10".

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seal had a balance of negative $4 in his saving account after making a deposit he has $25 in his account what is the overall cha

siniylev [52]

He deposited $29, so a $29 dollar difference

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3 years ago

At Sara's new job she spent $11.52, $6.48, $5.99, $14.00, and $9.50 on lunch the first week. In the second week, she spent $4 mo

elena55 [62]

The total amount that Sara spent for her meals during the first week is,
$11.52 + $6.48 + $5.99 + $14.00 + $9.50 = $47.49
With an average of $9.498

During the second week, she spent $4 more making her total equal to $51.49. The average is equal to $10.298. The increase in the mean is equal to,
increase in mean = $10.298 - $9.498 = $0.8Comments

4 0

3 years ago

Read 2 more answers

What is 3/5 written as a decimal? a 0.12 b 0.3 c 0.6 d 1.67

horsena [70]

Answer: 0.6 so c

Step-by-step explanation:

7 0

2 years ago

Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a

rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that $\sigma = 2$

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when $M = 0.5$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.5 = 1.96\frac{2}{\sqrt{n}}$

$0.5\sqrt{n} = 2*1.96$

Dividing both sides by 0.5

$\sqrt{n} = 4*1.96$

$(\sqrt{n})^2 = (4*1.96)^2$

$n = 61.5$

Rounding up

We would have to take a sample of 62 to achieve this result.

8 0

3 years ago

Mrs.Cranston bought five bottles of water for $0.90 each and 8 pounds of meat. She paid a total of $26.90 for these items, not i

Morgarella [4.7K]

Water = 5 bottles * $0.90 = $4.50
meat = 8 pounds * x amount.

Total = water + meat prices = $26.90
26.90 = $4.50 + 8x
22.40 = 8x
2.8 = x

The price per pound of meat is $2.80.

6 0

3 years ago