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3 years ago

Find m∠G, rounded to the nearest degree

Mathematics

1 answer:

julsineya [31]3 years ago

5 0

Answer:

d. $62\degree$

Step-by-step explanation:

The given triangle is a right triangle with all the sides given.

We can use any of the trigonometric ratios to find m<G.

Recall the mnemonics. SOH CAH TOA

Let us use the sine ratio.

$\sin(m\angle G)=\frac{Opposite}{Hypotenuse}$

$\sin(m\angle G)=\frac{15}{17}$

$m\angle G=\sin^{-1}(\frac{15}{17})$

$m\angle G=61.9$

$m\angle G=62\degree$ to the nearest degree.

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A store owner buys cell phones for $40 and marks up the price by 20%. Explained how to find the price at which she sells the cel

Gala2k [10]

Well depending on how you look at you could do $40 plus that extra 20% and since you said that means to add you would do the same price. as the actual price before you add that thirty 20% so you would add 40 plus 40 equals 80. If you did 25% the you would add 40 and 40 which is 80 and that's 20%out of 25% and add 5 to 80 and you get $85.

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4 years ago

What is 12a =? Talking about Math :/

frosja888 [35]

Answer: 12a=48

Step-by-step explanation:

4a+6b=10

4a=10-6b

a=(10-6b)/4

a=(5-3b)/2

2a-4b=12

2((5-3b)/2)-4b=12

(5-3b)-4b=12

5-7b=12

-7b=7

b=-1

2a-4b=12

2a-4(-1)=12

2a+4=12

2a=8

a=4

a=4, b=-1

12a=48

4 0

4 years ago

Please solve this sum asap

Oxana [17]

See attached photo for answers. let me know if you are doing rounding to a specific decimal.

3 0

3 years ago

Read 2 more answers

For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean

ki77a [65]

Answer:

$P(Z>3) = 1-P(Z$

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu=?,\sigma=?)$