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3 years ago

15

Heellppppp pleasee :)

1 answer:

denis23 [38]3 years ago

6 0

The answer to your question is 107.

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A sample of tritium-3 decayed to 94.5% of its original amount after a year.

Zolol [24]

(a) If $y(t)$ is the mass after $t$ days and $y(0) = A$ then $y(t) = Ae^{kt}.$

$y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945$

$\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\ ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}$

(b)
$Ae^{(\ln 0.945) t} = 0.20 A \ \Leftrightarrow\ (\ln 0.945) t \ln \frac{1}{5}\ \implies \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 28.45\text{ years}$

3 0

4 years ago

Given the equation -2x + 8y = 24, determine the x- and y-intercepts. PLZ HELP???

attashe74 [19]

Answer:

$x=(-12,0)$

$y=(0,3)$

Step-by-step explanation:

<u><em>x-intercept</em></u>

$-2(x-4y)=24$

$x-4y=-\frac{24}{2}$

$x-4y=-12$

$x=4y-12$

$x=4(0)-12$

$x=-12$

<u><em>y-intercept </em></u>

$-2(x-4y)=24$

$x-4y=-\frac{24}{2}$

$x-4y=-12$

$-4y=-12-x$

$y=-\frac{-12-x}{4}$

$y=-\frac{-12-(0)}{4}$

$y=\frac{12}{4}$

$y=3$

5 0

3 years ago

15 POINTS PLEASE ANSWER

faust18 [17]

Ok I have no idea if this is what it’s asking but I’ll give it a try

24inch=2 ft

2r=24 then r=12inch=1ft

V=πr^2.h

π.1.40= 40πft^3 so the answer I think is 40π

8 0

3 years ago

Which one of the sets below is a function explain why.

timama [110]

Answer:

functions cant have the same x vaule

im not sure which is a "set" since all the numbers are all under the same line

(3,4) (4,5) (5,6) (6,7) would be function

(1,6) (1,7) (3,4) (2,8) wouldnt be a function because of the 1

8 0

3 years ago

determine an equation and the radius for the circle that has its centre at the origin (0,0) passes through the point A 4-3

g100num [7]

Given:

The center of the circle is at (0,0).

The circle passes through the point A(4,-3).

To find:

The radius and the equation of the circle.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The radius of the circle is the distance between the points (0,0) and (4,-3).

$r=\sqrt{(4-0)^2+(-3-0)^2}$

$r=\sqrt{(4)^2+(-3)^2}$

$r=\sqrt{16+9}$

$r=\sqrt{25}$

$r=5$

So, the radius of the circle is 5 units.

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is center of circle and r is the radius.

Putting h=0, k=0, r=5, we get

$(x-0)^2+(y-0)^2=5^2$

$x^2+y^2=25$

Therefore, the radius of the circle is 5 units and the equation of the circle is $x^2+y^2=25$ .

6 0

3 years ago