Question

Find the solutions to the following linear-quadratic systems algebraically. Select the order pair that is one of the correct solutions from among the choices below.
y = -x² -x + 2
y = 2x + 2

(1, 0)
(3, 4)
(2, 0)
(-3, -4)

Answer 1

Answer:

(-3, -4)

Step-by-step explanation:

we have

$y=-x^{2} -x+2$ ----> equation A

$y=2x+2$ ----> equation B

equate equation A and equation B

$-x^{2} -x+2=2x+2$

$-x^{2} -x+2-2x-2=0$

$-x^{2} -3x=0$

$x(x+3)=0$

The solutions of the quadratic equation are x=0 and x=-3

Find the values of y

For x=0

$y=2(0)+2=2$

For x=-3

$y=2(-3)+2=-4$

therefore

The solutions of the system are the points (0,2) and (-3,-4)