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Talja [164]
3 years ago
9

Simplify the expression 2x^2 • 3x^0

Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

6x^2

Step-by-step explanation:

=2x^2•3x^0

=2x^2•3×1 (As any thing to the powe 0 is 1)

=2x^2•3

=2•3x^2

=6x^2

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Ella ordered 16 pizzas for a party.After the party there were 3 5/8 of pizza left.How many pizza were eaten?
erastovalidia [21]

Answer:

12 3/8

Step-by-step explanation:

16 -3 5/8 =12 3/8

to check:

12+3=15,

3/8+5/8= 8/8 which =1

so, 15+1=16

6 0
3 years ago
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1/3(m-1)=-5<br> Please help
dezoksy [38]

Answer:

m=-14 I hope this helps u

Step-by-step explanation:


6 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Solve the triangle given two angles and one side.
Rasek [7]

Answer:

a = 102.05

b = 393.76

B = 93°

Step-by-step explanation:

The law of sines tells you ...

a/sin(A) = b/sin(B) = c/sin(C)

Since the sum of angles in a triangle is 180°, angle B must be ...

B = 180° -72° -15° = 93°

and the unknown sides must be ...

a = c/sin(C)·sin(A) = 375·sin(15°)/sin(72°) ≈ 102.05192

B = 93°

b = 375·sin(93°)/sin(72°) ≈ 393.75796

_____

The rounding requirement got cut out of your picture, so we can't help you with that.

3 0
3 years ago
Find the diameter of a circle with an area of<br>95.03 square feet.<br>​
ra1l [238]

For this case we have that the area of a circle is given by:

A = \pi * r ^ 2

Where:

r: It is the radius of the circle

By clearing the radio we have:

r = \pm \sqrt {\frac {A} {\pi}}

We take the positive value:

r = \sqrt {\frac {A} {\pi}}\\r = \sqrt {\frac {95.03} {\pi}}\\r = 5.50 \ ft

The diameter is twice the radius:

d = 11

Answer:

11 \ ft

7 0
3 years ago
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