Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Let absolute variation in the wait time at the bus stop = v
Variation = ±3 minutes
Average bus run through the city = 15 minutes
Hence, the minimum and maximum run values due to the variation can be modeled as:
|variation - average run| = ±3
|v - 15| = ±3
minimum : v = - 3 +. 15 = 12 minutes
Maximum : v = 3 + 15 = 18 minutes
