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kozerog [31]
4 years ago
11

If i^2 = −1 and a = (i + 7), which is the result of squaring a?

Mathematics
1 answer:
Artyom0805 [142]4 years ago
8 0

Answer:

48+14i

Step-by-step explanation:

So squaring (i+7) looks like this

(i+7)^2

(i+7)(i+7)

Use foil.

First: i(i)=i^2=-1

Outer: i(7)=7i

Inner: 7(i)=7i

Last: 7(7)=49

____________Add the terms.

48+14i

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7 0
3 years ago
Answer number 1 please.​
Minchanka [31]

\sf {a}^{2}  =  {13}^{2}  -  {5}^{2}

Formula :

Base²= Hypotenuse² - Perpendicular ²

\\  \\

\hookrightarrow\sf {a}^{2}  =  {13}^{2}  -  {5}^{2}

\\  \\

\hookrightarrow\sf {a}^{2}  =169 - 25

\\  \\

\hookrightarrow\sf {a}^{2}  =144

\\  \\

\hookrightarrow\sf {a} = \sqrt{144}

\\  \\

\hookrightarrow\sf {a} = \sqrt{12 \times 12}

\\  \\

\hookrightarrow\sf {a} = 12

Remember the a² in formula has nothing to do with the a we have to find. :)

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