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Anika [276]
3 years ago
13

3(x+5)=2(3x-2) Help please! will mark brainliest!

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
3 0

Answer:

x=19/3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(x+5)=2(3x−2)

3x+15=6x+−4

3x+15=6x−4

Step 2: Subtract 6x from both sides.

3x+15−6x=6x−4−6x

−3x+15=−4

Step 3: Subtract 15 from both sides.

−3x+15−15=−4−15

−3x=−19

Step 4: Divide both sides by -3.

−3x

−3

=−19−3

x=19/3

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3 years ago
Jamie’s father has asked him to paint the fence around their home. If the fence is 119.5 years long, and Jamie can paint an aver
Citrus2011 [14]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Find the value of x 110, 40, 80
Deffense [45]
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5 0
4 years ago
Least to greatest -2/5 -2.47 -2 1/2 5 21/4
Yuliya22 [10]
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5 0
4 years ago
Celia has some cakes.
Vadim26 [7]

The carrot cakes are the fraction of the cake given by 1 - \frac{6}{7} multiplied by \frac{1}{3}

  • The fraction of the cakes that are carrot cakes is \underline {\dfrac{1}{21}}

<h3>How are the cakes evaluated as fractions?</h3>

The fraction of the cake that are chocolate cake = \dfrac{2}{3}

The fraction of the remaining cake that cheesecakes = \dfrac{6}{7}

The rest of the cakes = carrot cakes

Required:

The fraction of the cake that  are carrot cakes

Solution:

The fraction of the cakes that are not chocolate cake = 1 - \dfrac{2}{3} = \mathbf{ \dfrac{1}{3}}

The fraction of the remaining cakes that are cheesecake = \dfrac{6}{7} \times \dfrac{1}{3} = \mathbf{ \dfrac{6}{21}}

The fraction of the cake that are carrot cake = \dfrac{1}{3} - \dfrac{6}{7} \times \dfrac{1}{3} = \mathbf{\dfrac{1}{21}}

  • The fraction of the cakes that are carrot cake is \underline{\dfrac{1}{21}}

Learn more about fractions here:

brainly.com/question/3840488

5 0
2 years ago
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