Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Answer:
9
Step-by-step explanation:
a^2 + b^2 = h^2
15^2= 12^2 + b^2
225=144+b^2
81=b^2
9
The answer is d. i hope this helps!
Answer:
15x3y.
Step-by-step explanation:
.
Answer:
1/6
Step-by-step explanation:
P(red) = red/total
=6/36
=1/6
