Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
D x≥4
Step-by-step explanation:
−7 ≥ 13−5x
5x ≥ 20
x ≥ 4
<h2><u>CELL </u></h2>
<em>Cells are the basic building blocks of living things. The human body is composed of trillions of cells, all with their own specialised function. Cells are the basic structures of all living organisms.</em>
<h2>
<u>IMPORTANCE</u></h2>
<em>Cells provide structure for the body, take in nutrients from food and carry out important functions.</em>
<h3>
I HOPE THIS WILL HELP YOU IF NOT THEN SORRY </h3>
HAVE A GREAT DAY :)