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Monica [59]
3 years ago
15

What is the period of the function y = 2sin x?. A. 2Pi. B. Pi. C. [-2,2]. D. All Real Numbers

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

<h2>A. 2Pi</h2>

Step-by-step explanation:

The given function is

y=2sin(x)

Notice that the indepedent variable doesn't have any transformation, that means the period doesn't change. In other words, this function has the same period than its parent function which is 2\pi.

Therefore, the answer is A.

The image attached shows the graph of this function, there you can observe the period of the function.

Also, notice that this function is verticall stretched by a scale of 2, which doesn't change its original period.

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21 can go into 44 2 times

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3 years ago
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Can any one solve this.?
SpyIntel [72]

Answer:

x = 1

Step-by-step explanation:

Expand brackets

2x + 16 - 4x = 10x + 4

Rearrange so that x's are on one side and whole numbers are on the other

2x - 4x - 10x = 4 - 16

Simplify

-12x = -12

Make x on its own

x = 1

3 0
3 years ago
Joanne was hired by a florist to make large boes for holidays wreaths each roll of ribbon has 20 yards joanne used 3 1/2 rolls o
alukav5142 [94]

Answer: Each bow needs 4.67 yards of ribbon.

Step-by-step explanation:

We know that each roll has 20 yd.

She used 3 + 1/2 rolls, then the total length used will be (3 + 1/2) times the length of each roll, this is:

(3 + 1/2)*20 yd = (6/2 + 1/2)*20yd = (7/2)*20yd = 70 yd.

With tose 70 yards of ribbon, she made 15 bows, then the length of ribbon used in each bow will be equal to the quotient between the total length used and the number of ribbons made with it, this is:

70yd/15 = 4.67 yards

Each bow needs 4.67 yards of ribbon.

6 0
3 years ago
The exterior walls and roof of a barn are to be painted. The barn is in the shape of a rectangular prism, with an isosceles tria
vlada-n [284]

<u>Given:</u>

The rectangular prism has a length of 25 feet, a width of 10 feet and a height 55 feet.

The triangular prism has a base length of 25 feet, a height of 8 feet, and a prism height of 55 feet.

<u>To find:</u>

The total area to be painted.

<u>Solution:</u>

There are 4 external surfaces for the rectangular prism and 4 external surfaces for the triangular prism.

The rectangular prism has 4 rectangles out which there are 2 sets of similar rectangles.

There are two rectangles with lengths of 25 feet and widths of 10 feet while the other two rectangles have lengths of 55 feet and widths of 10 feet.

The area of a rectangle with a length of 25 feet and a width of 10 feet = 25(10)= 250 square ft.

The area of two such rectangles = 2(250) = 500 square feet.

The area of a rectangle with a length of 55 feet and a width of 10 feet = 55(10)= 550 square feet.

The area of two such rectangles = 2(550) = 1100 square feet.

The triangular prism has 2 triangles and 2 rectangles.

The triangles have base lengths of 25 feet and heights of 8 feet while the rectangles have lengths of 55 feet and heights of 14.8 feet.

The area of a triangle with a base length of 25 feet and a height of 8 feet = \frac{1}{2}(25)(8)= 100 square feet.

The area of two such triangles =2(100)= 200 square feet.

The area of a rectangle with a length of 55 feet and a width of 14.8 feet = 55(14.8)= 814 square feet.

The area of two such rectangles = 2(814) = 1628 square feet.

The total area to be painted =500+1100+200+1628 = 3128 square feet.

So an area of 3128 square feet is to be painted.

8 0
3 years ago
During a game, Naomi lost points. She lost fewer
finlep [7]
The answer is 1 or 2.
6 0
3 years ago
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