Answer:
a. Project A requires an up-front expenditure of $1,000,000 and generates a net present value of $3,200.
Explanation:
a.
The company should accept project A because it provides a positive net present value of $3,200 that is the highest among all the projects.
b.
When the IRR of a project is lower than the required rate of return of the project, it will generate the negative net present value because at IRR the net present value of the project will be zero and at a higher rate than IRR it will be negative.
c.
The project with a profitability index of less than 1 generates a negative NPV because the present value of future cash flows is less than the initial cash outflow.
d.
Project D also generates a positive net present value but it is lower than project A. So, after comparing the results we will choose the project with higher NPV.
A loan is usually gotten from a financial institution to solve a financial emergency which was unplanned for.
<h3>What is a Loan?</h3>
This refers to the obtaining of money from a financial institution and a formal agreement is made for the repayment of the money after a given period of time and with interest.
With this in mind, we can see that loan proceeds can be used to:
- Buy a house
- Go on a trip, etc
Please note that your question is incomplete so I gave you a general overview to help you get better understanding of the concept.
Read more about loans ere:
brainly.com/question/25239160
Answer:
B) diminishing marginal utility
Explanation:
The law of Diminishing marginal utility states that utility falls as consumption increases.
The law of demand states that the higher the price, the lower the quantity demanded and the lower the price, the higher the quantity demanded.
Because of diminishing marginal utility, consumption can be encouraged by reducing price.
As utility falls, consumers would be unwilling to buy more goods at the same price, therefore it would be reasonable to reduce price to encourage consumption.
Hey There!:
Sample Mean = 4.4823
SD = 0.1859
Sample Size (n) = 7
Standard Error (SE) = SD/root(n) = 0.0703
alpha (a) = 1-0.99 = 0.01
t(a/2, n-1 ) = 3.7074
Margin of Error (ME) = t(a/2,n-1)x SE = 0.2606
99% confidence interval is given by:
Sample Mean +/- (Margin of Error)
4.4823 +/- 0.2606 = (4.222 , 4.743)
Hope this helps!
Wher do we choose the communication planning and resource?
