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Fantom [35]
3 years ago
12

Given sin(theta)= 7/11 and sec(theta)<0 Find cos(theta) and tan(theta)

Mathematics
2 answers:
Simora [160]3 years ago
7 0

Answer:

cos∅ = -\frac{6\sqrt{2} }{11}

Step-by-step explanation:

allsm [11]3 years ago
3 0
When given a trigonometric ratio, and asked to find another ratio, we draw a right triangle as shown in the picture.

From the pythagorean theorem we find the length of AB:

 |AB|= \sqrt{ AC^{2}- BC^{2} }=  \sqrt{ 11^{2}- 7^{2} }= \sqrt{121-49} = \sqrt{72} =  \sqrt{2*36} = 6\sqrt{2}

the numerical value of

cos∅=adjacent side/hypotenuse=\frac{ 6 \sqrt{2} }{11}

since sec∅=1/cos∅, and sec∅ is negative, then cos∅ is also negative.


Answer: 

cos∅=-\frac{ 6 \sqrt{2} }{11}

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