Answer:
see explanation
Step-by-step explanation:
Given
6a² - a - 5 = 0
Consider the factors of the product of the a² term and the constant term which sum to give the coefficient of the a- term.
product = 6 × - 5 = - 30 and sum = - 1
The factors are - 6 and + 5
Use these factors to split the a- term
6a² - 6a + 5a - 5 = 0 ( factor the first/second and third/fourth terms )
6a(a - 1) + 5(a - 1) = 0 ← factor out (a - 1) from each term
(a - 1)(6a + 5) = 0
Equate each factor to zero and solve for a
a - 1 = 0 ⇒ a = 1
6a + 5 = 0 ⇒ 6a = - 5 ⇒ a = - ![\frac{5}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D)
Solution set = { 1, -
}
8 books with 2 sheets each and 1 extra sheet as leftover
Answer:
True
Step-by-step explanation:
The sum of cubes a^ 3 + b^ 3 = (a + b) (a ^2 − a b + b^ 2 )
We need to determine if 216x^3 is a cube and 64 is a cube
216 = 6*6*6
216 x^3 = (6x) ^3
and 64 = 4*4*4 = 4^3
So 216x^3 +64 = (6x)^3 + 4^3
Answer:
I don't know
Step-by-step explanation:
what
i dont know what that is
Since it is on the left up corner, its in quadrant 2