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Ivan
3 years ago
12

Need help ASAP please

Mathematics
2 answers:
Butoxors [25]3 years ago
7 0
1) 78.6

2) 69.37

3) 37.4

ser-zykov [4K]3 years ago
6 0
Hi. Here are the answers and I am adding an image that shows the first one step by step. The steps would be the same for any problems like these. I hope it helps.

708÷9 = 78 6/9 which reduces to 78 2/3

555÷8= 69 3/8

192÷5= 38 2/5

If you have any questions, please don't hesitate to ask.

Take care,
Diana

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luda_lava [24]
No, .7 is indirectly 70 and .3 is indirectly 30 and 70 is bigger than 30 so no .3 is not bigger than .7
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3 years ago
I need the product of a^4xa^6
emmainna [20.7K]
A^4 * a^6

exponent rule : x^y * x^z = x^(y + z)

so, a^4 * a^6 = a^(4 + 6) = a^10
3 0
3 years ago
In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311
Bingel [31]

Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

Z_{1-\alpha /2}= Z_{0.975}= 1.965

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

√V(X)= 6.45

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

5 0
4 years ago
The number of points that lie on a period at the end of sentence are
Airida [17]
Infinite is your answer :)
7 0
3 years ago
PLEASE PLEASE HELP MEH
wel
Answer is in bold and i will add step
Since they are vertical angles they will be the same. Since 6=146 2=146

4 0
3 years ago
Read 2 more answers
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