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marshall27 [118]
3 years ago
11

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

Mathematics
2 answers:
Sauron [17]3 years ago
7 0

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

15L

Alex73 [517]3 years ago
3 0
The solution is 25% acid, which means 2.5 liters acid (10 x .25). 
<span>you need that 2.5 liters to be 10%, or 1/10th the total. </span>
<span>the total would have to be 25 liters (2.5 x 10) so when you add to 10 to get 25 you get </span><span>15 liters. Hope I helped!</span>
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