Question

A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?

Answer 1

Answer:$P=\dfrac{4}{15}$

Step-by-step explanation:

Given

Bag contains 4 yellow marble and 6 green marble

If the marble is not replace after the first withdrawal

Probability that the first marble is green and the second one is yellow

$P(1)=$Choosing first marble as green out of 10 marble

$P(2)=$Choosing second marble as yellow out of 9 marble

$P=P(1)\times P(2)$

$P=\dfrac{^6C_1}{^{10}C_1}\times \dfrac{^4C_1}{9^C_1}$

$P=\dfrac{4}{15}$