You can test this using the equation: a^2 + b^2 = c^2.
24^2 + b^2 = 60^2
576 + b^2 = 3,600
b^2 = 3,024
b = 54.999
Since b is not a whole number, the side lengths do not form a Pythagorean triple.
Brainliest answer please!!!
Answer:
1) -10^3 (-10 to the power of 3)
2) r^5 (pie to the power of 5)
3) 1/2^2 + x^3 (1/2 to the power of 2 + x to the power of 3)
Answer:
y = -1/2x +6
Step-by-step explanation:
We can use the slope intercept form of a line
y = mx+b where m is the slope and b is the y intercept
y = -1/2x +b
Substitute the point into the equation
9 = -1/2 (-6) +b
9 = 3+b
9-3 =b
6 =b
y = -1/2x +6
You want to figure out what the variables equal to, all of these are parallelograms meaning opposite sides and angles are equal to each other.
In question 1 start with 3x+10=43, this means that 3x is 10 less than 43 which is 33, 33 divided by 3 is 11 meaning x=11.
Same thing can be done with the sides 124=4(4y-1), start by getting rid of the parentheses with multiplication to get 124=16y-4, this means that 16y is 4 more than 124, so how many times does 16 go into 128? 8 times, so x=11 and y=8
Question 2 can be solved because opposite angles are the same in a parallelogram, so u=66 degrees
You can find the sum of the interial angles with the formula 180(n-2) where n is the number of sides the shape has, a 4 sided shape has a sum of 360 degrees, so if we already have 2 angles that add up to a total of 132 degrees and there are only 2 angles left and both of those 2 angles have to be the same value then it’s as simple as dividing the remainder in half, 360-132=228 so the other 2 angles would each be 114, 114 divided into 3 parts is 38 so u=66 and v=38
Question 3 and 4 can be solved using the same rules used in question 1 and 2, just set the opposite sides equal to each other
Answer:
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.
A. The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.
C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.
E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake
The answer is E.
