Quadratic equation which has no solution gives zero for the value of d.
d = b² - 4ac
0 = 3² +- 4(-1)c
-9 = +_ 4c
c = -9/-4 pr 9/-4
c = 9/4 or -9/4
In short, Your Answers would be Option C & E
Hope this helps!
A B C D E represent the subjects
A+A1
A+B2
A+C3
A+D4
A+E5
B+B6
B+C7
B+D8
B+E9
C+C10
C+D11
C+E12
D+D13
D+E14
E+E15
15 combos
Answer:
D
Step-by-step explanation:
This is exponential growth, and to my understanding, the format goes:
<em>initial amount (percent growth/ decay)^time</em>
percent growth = (<em>decimal percent + 1)</em>
<em>percent decay = (1 - decimal percent) </em>
Your equation:
1500(1.02)^t
Using the above format, 1500 appears to be the initial amount, which increases by 2% per annum.
i think
We are given
Set A: {(5,1), (4,4), (3,9), (2,16), (1,25)}
We can see that for each x value of the set is increasing exponentially.
<h3>We can set up a rule for it y = (6-x)^2</h3>
y=(6-5)^2 = (1)^2 = 1
y=(6-4)^2 = (2)^2 = 4
y=(6-3) = (3)^2 = 9
y=(6-2)^2 = (4)^2 = 16
y=(6-1)^2 = (5)^2 = 25.
For set B:
Set B: {(1,-5), (2,-3), (3,-1), (4,1), (5,3)}
It's simply linear function as diffrences of y values are constant that is 2.
<h3>We can set a rule for it : y = 2x - 7.</h3>
y = 2(1) -7 = 2-7 = -5
y = 2(2) -7 = 4-7 = -3
y = 2(3) -7 = 6-7 = 1
y = 2(4) -7 = 8-7 = 1
y = 2(5) -7 = 10-7 = 3.