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DerKrebs [107]
3 years ago
11

the ratio of boys to girls are 8 to 7. if there was a total of 195 students, how many boys and girls are there?

Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0
Add the values of the ratio.

8+7= 15

Boys: 195/15= 13(8)=104

Girls: 195/15= 13(7)= 91

There are 104 boys and 91 girls. Hope this helps!
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Charles has rolled a 6-sided die three times and it landed on 3 each time. What is the probability of getting a 3 on the 4th rol
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The answer would be D - 1/6


This is because there are six sides to the die and just because he rolled all 3s before it does not mean he has a better chance to roll a 3 now.

Since there is only 1 3 on the six sided die there is a 1/6 chance he would roll a 3.

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3 years ago
How are rigid transformations used to justify the SAS congruence theorem?
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Answer:

When a shape is transformed by rigid transformation, the sides lengths and angles remain unchanged.

Rigid transformation justifies the SAS congruence theorem by keeping the side lengths and angle, after transformation.

Assume two sides of a triangle are:

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When the triangle is transformed by a rigid transformation (such as translation, rotation or reflection), the corresponding side lengths and angle would be:

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Step-by-step explanation:

5 0
1 year ago
2(a-3)÷(a-4)(a-5)+a-1÷(3-a)(a-4)+a-2÷(5-a)(a-3) simplify.​
Arlecino [84]

<u><em>I'm almost confident that I did this wrong, but i tried...</em></u>

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4a-9 ÷ -19

Step-by-step explanation:

(It was easier for me to put it in fractions)

\frac{2(a-3)}{(a-4)(a-5)} + \frac{a-1}{(3-a)(a-4)} + \frac{a-2}{(5-a)(a-3)}        (3-a) (a-4) + (5-a) (a-3)

\frac{2a-6}{(a-4)(a-5)} + \frac{a-1}{(3-a)(a-4)} +  \frac{a-2}{(5-a)(a-3)}      3 - a · a - 4 + 5 - a · a - 3

    \frac{2a-6}{(2a-20)} + \frac{a-1}{(3-a)(a-4)} + \frac{a-2}{(5-a)(a-3)}               3 - a + 1 - a - 3

   \frac{2a-6+a-1+a-2}{(2a-20)+(3-a)(a-4)+(5-a)(a-3)}                        1 - a - a

                 \frac{4a-9}{2a-20+1-2a}                                       1 - 2a

                   \frac{4a-9}{2a-19-2a}

                      \frac{4a-9}{-19}

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