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2 years ago

Evaluate 3p/q when p=2and q=6

Mathematics

2 answers:

sukhopar [10]2 years ago

7 0

$\frac{3p}{q}\\\\subtitute\ p=2\ and\ q=6\ to\ \frac{3p}{q}:\\\\\frac{3\cdot2}{6}=\frac{6}{6}=1\leftarrow Answer$

Ira Lisetskai [31]2 years ago

6 0

So we know what the variables are already.

$\frac{3*2}{6}$

Now, 3 x 2 = 6.

So our fraction is 6/6.

6/6 is also equal to 1.

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One hundred employees of a company are asked how they get to work and whether they work full time or part time. The table below

inna [77]

The probability is 56/100, or 14/25 = 0.56.

These events are not mutually exclusive, meaning they can happen at the same time. This means we use

P(A or B) = P(A) + P(B) - P(A and B)

P(carpool or full time) = P(carpool) + P(full time) - P(carpool & full time)

There are 6+9=15 people out of 100 that carpool.
There are 7+4+30+6=47 people out of 100 that work full time.
There are 6 people out of 100 that carpool and work full time.

This gives us
15/100 + 47/100 - 6/100 = 56/100

5 0

3 years ago

St 2

Lubov Fominskaja [6]

Answer:

$5.5

Step-by-step explanation:

6 * N (notebook) + 3 * P (pen) = 27

n = 1.5 +P

6 * (1.5 + P) + 3 * P = 27

9 +6p +3p = 27

9p = 18

p (pen): $2

N (notebook): $3.5

combined cost of 1 pen and 1 notebook: $2 + $ 3.5 = $ 5.5

3 0

3 years ago

PLEASE HELP QUICK!! If the local tax is 3% and you get paid $678 biweekly, what is the local tax deduction?

Anastasy [175]

tax reduction: $20.34

amount you're paid minus tax: $657.66

4 0

3 years ago

In a random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand. C

horrorfan [7]

Answer:

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

Step-by-step explanation:

Step(i):-

Given sample size 'n' =300

Given data random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.

Given sample proportion

$p^{-} = \frac{x}{n} = \frac{182}{300} =0.606$

level of significance = 90% or 0.10

Z₀.₁₀ = 1.645

90% confidence interval for the proportion is determined by

$(p^{-} - Z_{0.10}\sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.10}\sqrt{\frac{p(1-p)}{n} })$

$(0.6066 - 1.645\sqrt{\frac{0.6066(1-0.6066)}{300} } ,0.6066+1.645\sqrt{\frac{0.6066(1-0.6066)}{300} })$

(0.6066 - 0.0463 ,0.6066 + 0.0463)

(0.5603,0.6529)

final answer:-

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

5 0

3 years ago

At sunrise, the temperature was -12 °F. The temperature increased 19 °F each hour for 3 hours. What was the temperature 3 hours

yawa3891 [41]

-12 degree F + 19 + 19 + 19 = 49 degree F
I think the answer is 49 degree F...

4 0

3 years ago