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3 years ago

Evaluate 3p/q when p=2and q=6

Mathematics

2 answers:

sukhopar [10]3 years ago

7 0

$\frac{3p}{q}\\\\subtitute\ p=2\ and\ q=6\ to\ \frac{3p}{q}:\\\\\frac{3\cdot2}{6}=\frac{6}{6}=1\leftarrow Answer$

Ira Lisetskai [31]3 years ago

6 0

So we know what the variables are already.

$\frac{3*2}{6}$

Now, 3 x 2 = 6.

So our fraction is 6/6.

6/6 is also equal to 1.

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Pleas help i will give a lot of points IF you answer this ?

avanturin [10]

Answer:

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Step-by-step explanation:

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3 years ago

Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

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3 years ago

Eden bought a new phone. The phone's retail price is $199. In addition, she paid sales tax of 8% of the retail price. A few days

natka813 [3]

Answer:

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3 years ago

astronauts use a tool in space that weighs 5 ounces on Earth. How many grams does the tool weigh? Round your answer to the neare

erik [133]

First you need to find how many grams is 1 ounce. 1o z.is 28.35 g, then you need to multiply 28.35 g by 5 which is 141.75. you need to round it to the nearest hundred so it is about 142 grams.

the key here would be

1 oz. = 28.35g or 1 oz. = 28 g

Hope this helps!

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3 years ago

Read 2 more answers

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My name is Ann [436]

Answer:

Addition. “Also, I have to stop at the store on the way home.” ...

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Concession. “Granted, you did not ask ahead of time.” ...

Step-by-step explanation:

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3 years ago