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3 years ago

2ones is the same as 20 tenth.Explain

Mathematics

1 answer:

babymother [125]3 years ago

3 0

How did you get that as an answer ?

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When positive integer x is divided by positive integer y, the remainder is 9. If = 96.12, what is the value of y ? 96 75 48 25 1

NeTakaya

Y= 75.

Lets try to solve it,

When positive integer x is divided by positive integer y, the remainder is 9

=> x=qy+9;

=> x/y=96.12

=>x=96y+0.12y (so q above equals to 96);

=>0.12y=9

=> y=75.

Hence the value of y would be 75.

Learn more about Positive Integer on:

brainly.com/question/1367050

#SPJ4

4 0

2 years ago

Foster is centering a photo that is 7 / 1 2 inches wide on a scrapbook page that is 14 inches wide. How far from each side of th

Snowcat [4.5K]

36 inches long divide by 7 and 12

6 0

3 years ago

A farmer will divide a 1/4 acre plot of land into three equal-sized sections what will be the size of each section?

Natalija [7]

1/4:3= 1/4•1/3=1/12acre - size of each section

1/2•1/5=1/10yard

8 0

3 years ago

Read 2 more answers

Find the median and mean of the data set below:<br> 47,15, 6, 49, 45, 30

Georgia [21]

Answer:

The median of the data set:

6, 15, 30, 45, 47, 49

The middle numbers are 30 and 45 so

You have to do 30 + 45

= 75

Then do 75 ÷ 2

= 37.5

The mean of the data set:

47, 15, 6, 49, 45, 30 (add them all)

= 192

Then divide 192 by 6 (because there are 6 numbers)

192 ÷ 6

= 32

So the median is 37.5 and the mean is 32.

Step-by-step explanation:

Hope this helps!

From your neighborhood softie :)

5 0

2 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .

The probability that both $A$ and $B$ occurs will be:

$\displaystyle P(A \cap B) = P(B\cap A) = P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}$ .

6 0

3 years ago